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This is a very simple dice roll program that keeps rolling two dice until it gets double sixes. So my while statement is structured as:

while DieOne != 6 and DieTwo != 6:
For some reason, the program ends as soon as DieOne gets a six. DieTwo is not considered at all.
But if I change the and to an or in the while statement, the program functions perfectly. This doesn't make sense to me. 
import random
print('How many times before double 6s?')
num=0
DieOne = 0
DieTwo = 0
while DieOne != 6 or DieTwo != 6:
    num = num + 1
    DieOne = random.randint(1,6)
    DieTwo = random.randint(1,6)
    print(DieOne)
    print(DieTwo)
    print()
    if (DieOne == 6) and (DieTwo == 6):
        num = str(num)
        print('You got double 6s in ' + num + ' tries!')
        print()
        break
                If DieOne is 6 then the statement DieOne != 6 and DieTwo != 6 is false because it's not true the both die are not equal to six.
– Mark
                Jan 12, 2019 at 19:34
                That makes sense to me, so it's unclear what you're asking. You want the loop to end when both checks are false, so or is the correct combination.
– jonrsharpe
                Jan 12, 2019 at 19:34
                the problem is this. you want NOT(die 1 is 6 AND die 2 is 6). The equivalent condition becomes die 1 is NOT 6 OR die 2 is NOT 6. This is a logic problem that you'd need to work out. when you say "die 1 is not 6 AND die 2 is not 6", the condition will immediately fail the moment one of them become a 6, because AND needs to ensure BOTH conditions stay satisfied.
– Paritosh Singh
                Jan 12, 2019 at 19:37
TLDR at bottom.
First off, while loops run if the following condition is true, so
DieOne != 6 or DieTwo != 6:
must return true when simplified, for the while funtion to run
The and operator returns true if both conditions are true, so the while loop will only run when it is True and True.
So the following won't run if either of the dice rolled a 6 for example:
while DieOne != 6 and DieTwo != 6:
If DieOne rolled a 4 and DieTwo rolled a 6, the while loop won't run because DieOne != 6 is true, and DieTwo != 6 is false. I put this train of thought into code below.
while DieOne != 6 and DieTwo != 6:
while True and False:
while False: #So it won't run because it is false
The or operator works differently, the or operator returns true when one of the conditions is true, so the while loop will run when it is True or True, True or False, or _False or True.
while DieOne != 6 or DieTwo != 6:
will run if only either dice rolled a six. For example:
If DieOne rolled a 4 and DieTwo rolled a 6, the while loop will run because DieOne != 6 is true, and DieTwo != 6 is false. I put this train of thought into code below.
while DieOne != 6 or DieTwo != 6:
while True or False:
while True: #So it will run because it is true
TLDR/Review:
while True: #Will run
while False: #Won't run
while True and True: #Will run
while True and False: #Won't run
while False and True: #Won't run
while False and False: #Won't run
while True or True: #Will run
while True or False: #Will run
while False or True: #Will run
while False or False: #Won't run
                Good try, but this runs into the same problem as my original code. It works if you change the Or operator to And.
– ghulseman
                Oct 11, 2021 at 22:45
   if (DieOne == 6) and (DieTwo == 6):
      num = str(num)
      print('You got double 6s in ' + num + ' tries!')
      print()
      break
                While this code may answer the question, providing additional context regarding how and/or why it solves the problem would improve the answer's long-term value. You can find more information on how to write good answers in the help center: stackoverflow.com/help/how-to-answer . Good luck 🙂
– nima
                Oct 8, 2021 at 21:38
Hmm. Boil it down to a single condition, both_6:bool, based on multiple conditions:
import random
num = 0
both_6 = False
while not both_6:
    num += 1
    DieOne = random.randint(1,6)
    DieTwo = random.randint(1,6)
    if (DieOne==6) and (DieTwo==6):
        both_6 = True
        print(f"\nIt took you {num} attempts to get double sixes!\n")
It took you 25 attempts to get double sixes!
It feels like multiple conditions is broken
        
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