[错误] TypeError: sequence item 0: expected str inst

TypeError: sequence item 0: expected str instance, int found

list包含数字，不能直接转化成字符串

小例子：

a = ['1','2','3',1]
print(' '.join(a))

报错：

Traceback (most recent call last):
  File "C:/Users/Administrator/Desktop/onetest.py", line 188, in <module>
    print(' '.join(a))
TypeError: sequence item 3: expected str instance, int found

解决办法：

print(" ".join('%s' %id for id in list1))

即遍历list的元素，把他转化成字符串。这样就能成功输出1 2 3 1了。

参考：

TypeError: sequence item 0: expected str instance, int found的解决办法