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I have a website that hosts videos from a client. On the website the files load externally via m3u8 link.
The client would now like to have those videos on a Roku channel.
If I simply use the m3u8 link from the site it gives an error because the url generated is sent with a cookie and so a client must click and the link to generate a new code for them.
I would like if possible (and I have not seen this here) is to scrape the html page and just return the link via PHP script on the website from the Roku.
I know how to get titles and such using pure php but am having problems returning the m3u8 link..
I do have code to show I am not looking for handouts and actually am trying.
This is what I have used for getting the title name for example.
Note: I would like to know if it is possible to have one php that autofills the html page per url so I do not have to use a different php for each video with the url pretyped in.
$html = file_get_contents('http://example.com'); //get the html returned from the following url
$movie_doc = new DOMDocument();
libxml_use_internal_errors(TRUE); //disable libxml errors
if(!empty($html)){ //if any html is actually returned
$movie_doc->loadHTML($html);
libxml_clear_errors(); //remove errors for yucky html
$movie_xpath = new DOMXPath($movie_doc);
//get all the titles
$movie_row = $movie_xpath->query('//title');
if($movie_row->length > 0){
foreach($movie_row as $row){
echo $row->nodeValue . "<br/>";
–
There is a simple approach for this, which involves using regex.
In this example let's say the video M3u8 file is located at:
http://example.com/theVideoPage
You would point the video URL Source in your XML to your PHP file.
http://thisPhpFileLocation.com
$html = file_get_contents("http://example.com/theVideoPage");
preg_match_all(
'/(http.*m3u8)/',
$html,
$posts, // will contain the article data
PREG_SET_ORDER // formats data into an array of posts
foreach ($posts as $post) {
$link = $post[0];
header("Location: $link");
Now if you want to use a URL that you can append a URL link at the end it could look something like this and you would use an address as such for a Video Url located at
http://thisPhpFileLocation.com?id=theVideoPage
$id = $_GET['id'];
$html = file_get_contents("http://example.com".$id);
preg_match_all(
'/(http.*m3u8)/',
$html,
$things, // will contain the article data
PREG_SET_ORDER // formats data into an array of posts
foreach ($things as $thing) {
$link = $thing[1];
// clear out the output buffer
while (ob_get_status())
ob_end_clean();
// no redirect
header("Location: $link");
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