获取给定的Lat/Long bbox矩形的精确卫星图像？

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curl -g "https://api.mapbox.com/styles/v1/mapbox/streets-v11/static/[17.55490,47.10434,17.55718,47.10543]/600x419?access_token=YOUR_TOKEN_HERE" --output example-walk-600x419-nopad.png

Wm = Wd
Hm = Wd * (y2 - y1) * cos(x1) / (x2 - x1)

curl -g "https://api.mapbox.com/styles/v1/mapbox/streets-v11/static/[<x1>,<y1>,<x2>,<y2>]/<Wm>x<Hm>?access_token=<YOUR_TOKEN>" --output overlay.png
If (Hd == Hm) 
  then {you are lucky :) the two images just fit each other}
  else { the two images are for the same area, but you have to scale the height of one of the images to make match }

      Lon1            Lon2
Lat1   +---------------+
       |               |
       |               |
Lat2   +---------------+

var maxHoleLat = 52.5738902
var maxHoleLon = 4.9577606
var minHoleLat = 52.563994
var minHoleLon = 4.922364
var mapMaxLat = 0.0
var mapMaxLon = 0.0
var mapMinLat = 0.0
var mapMinLon = 0.0
let token = "your token"
var resX = 1000.0
var resY = 1000.0
let screenX = 184.0
let screenY = 224.0 // 448/2 = 224 - navbarHeight
let navbarHeight = 0.0
var latDist = 111000.0
var lonDist = 111000.0
var dx = 0.0
var dy = 0.0
func latLonDist(){
    //calgary.rasc.ca/latlong.htm
    let latRad = maxHoleLat * .pi / 180
    //distance between 1 degree of longitude at given latitude
    self.lonDist = 111412.88 * cos(latRad) - 0.09350*cos(3 * latRad) + 0.00012 * cos(5 * latRad)
    print("lonDist = \(self.lonDist)")
    //distance between 1 degree of latitude at a given longitude
    self.latDist = 111132.95 - 0.55982 * cos(2 * latRad) + 0.00117 * cos(4 * latRad)
    print("latDist = \(self.latDist)")
func getMapUrl(){
     self.dx = (maxHoleLon - minHoleLon) * lonDist
     self.dy = (maxHoleLat - minHoleLat) * latDist
    //the map is square, but the hole not
    //check if the hole has less x than y
    if dx < dy {
        mapMaxLat = maxHoleLat
        mapMinLat = minHoleLat
        let midLon = (maxHoleLon + minHoleLon ) / 2
        mapMaxLon = midLon + dy / 2 / lonDist
        mapMinLon = midLon - dy / 2 / lonDist
    } else {
        mapMaxLon = maxHoleLon
        mapMinLon = minHoleLon
        let midLat = (maxHoleLat + minHoleLat ) / 2
        mapMaxLat = midLat + dx / 2 / latDist
        mapMinLat = midLat - dx / 2 / latDist

获取给定的Lat/Long bbox矩形的精确卫星图像？

3 个回答