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The % signs need to go in the variable that you assign to the parameter, instead of in the query.
I don't know if you're using mysqli or PDO, but with PDO it would be something like:
$st = $db->prepare("SELECT * FROM table WHERE name LIKE ?");
$st->execute(array('%'.$test_string.'%'));
For mysqli
user the following.
$test_string = '%' . $test_string . '%';
$st->bind_param('s', $test_string);
$st->execute();
–
SELECT * FROM table WHERE name LIKE '%' || :param || '%'
# mysql
SELECT * from table WHERE name LIKE CONCAT('%', :param, '%')
I'm not familar with other databases, but they probably have an equivalent function/operator.
–
–
in PHP using MYSQLI you need to define a new parameter which will be declared as:
$stmt = mysqli_prepare($con,"SELECT * FROM table WHERE name LIKE ?");
$newParameter='%'.$query.'%';
mysqli_stmt_bind_param($stmt, "s", $newParameter);
mysqli_stmt_execute($stmt);
this works for me..
$connection = new mysqli($dbServer, $dbUserName, $dbPassword, $dbName);
if($connection->connect_errno)
exit("Database Connection Failed. Reason: ".$connection->connect_error);
$tempFirstName = "reuel";
$sql = "SELECT first_name, last_name, pen_name FROM authors WHERE first_name LIKE CONCAT(CONCAT('%',?),'%')";
//echo $sql;
$stateObj = $connection->prepare($sql);
$stateObj->bind_param("s",$tempFirstName);
$stateObj->execute();
$stateObj->bind_result($first,$last,$pen);
$stateObj->store_result();
if($stateObj->num_rows > 0) {
while($stateObj->fetch()){
echo "$first, $last \"$pen\"";
echo '<br>';
$stateObj->close();
$connection->close();
I will just adapt Chad Birch's answer for people like me who are used to utilize bindValue(...)
for PDO:
$st = $db->prepare("SELECT * FROM table WHERE name LIKE :name");
$st->bindValue(':name','%'.$name.'%',PDO::PARAM_STR);
$st->execute();
The sprintf can do it. Remember to put another % in front of the original % to escape it.
$ret = sprintf("SELECT * FROM table WHERE name LIKE %%%s%%", $name);
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