问 查找字符串是否位于二维VBA Excel数组中

@Siddharth上面的答案除了 Application.Match 函数:-)外，还与 Filter 完美地工作在一起。-我的解决方案只尝试使用OP Filter 函数:由于过滤器函数需要一个1昏暗的数组，所以数组被分割成部分。

A)使用原始筛选函数而不是匹配加上错误处理的替代解决方案

Function IsInArray(stringToBeFound As String, arr As Variant) As Boolean
Dim i      As Long
If nDim(arr) = 1 Then
  IsInArray = (UBound(Filter(arr(), stringToBeFound)) > -1)
Else    ' allows using filter function in portions
  For i = 1 To UBound(arr, 2)
      If (UBound(Filter(Application.Transpose(Application.Index(arr, 0, i)), stringToBeFound)) > -1) Then IsInArray = True: Exit For
  Next i
End If
End Function

帮助函数获取数组维数

Function nDim(ByVal vArray As Variant) As Long
' Purp: get number of array dimensions
' Site: http://support.microsoft.com/kb/152288
  Dim dimnum     As Long
  Dim ErrorCheck As Variant
  On Error GoTo FinalDimension
  For dimnum = 1 To 60000
      ErrorCheck = LBound(vArray, dimnum)
FinalDimension:
  nDim = dimnum - 1
End Function

B)递归解决方案 使用原始的过滤函数而不是匹配加上错误处理

Function IsInArray(stringToBeFound As String, arr As Variant, Optional i As Long = 0) As Boolean
Select Case i
       Case -1:                                                             ' stop 2dim calls
       Case 0: IsInArray = IsInArray(stringToBeFound, arr, nDim(arr))       ' start recursive call
       Case 1: IsInArray = (UBound(Filter(arr(), stringToBeFound)) > -1)    ' 1dim array
       Case Else           ' allows using filter function in portions
            If (UBound(Filter(Application.Transpose(Application.Index(arr, 0, i)), stringToBeFound)) > -1) Then