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In my get_keypair function,I want to create an EC_KEY structure by EC_KEY_new_by_curve_name(NID_secp256k1) .By doing so,I got a crash on my vs2019 with no details.Below comes my code.

bool get_keypair(EC_KEY** key, bool getcompressed,uint8_t* rawprikey,  uint8_t rawprikeylen) {
    BIGNUM* priv; //prikey bignum
    BN_CTX* ctx; //hold the operation
    const EC_GROUP* group;
    EC_POINT* pub; //pubkey point st
    *key = EC_KEY_new_by_curve_name(NID_secp256k1); //secp256k1, !!!crashed here
    if (*key == 0) {
        printf("new ec key failed");
        exit(-1);
    priv = BN_new(); //create bignum
    BN_bin2bn(rawprikey, 32, priv); //fill the bigbum with prikey
    EC_KEY_set_private_key(*key, priv); //put prikey bignum to key pair
    ctx = BN_CTX_new(); //create context
    BN_CTX_start(ctx); //init context
    group = EC_KEY_get0_group(*key); //G
    pub = EC_POINT_new(group); //create pub st
    EC_POINT_mul(group, pub, priv, NULL, NULL, ctx); //P = n * G
    EC_KEY_set_public_key(*key, pub); //fill the key pair, !!!crashed here
    EC_KEY_set_conv_form(*key, getcompressed ? POINT_CONVERSION_COMPRESSED : POINT_CONVERSION_UNCOMPRESSED); //compressd or not 
    uint64_t pubkeylen = i2o_ECPublicKey(*key, NULL);
    uint8_t *pubkey = calloc(pubkeylen, sizeof(uint8_t));
    uint8_t* pub_copy = pubkey;
    if (i2o_ECPublicKey(*key, &pub_copy) != pubkeylen) {
        puts("Unable to decode public key");
        return false;
    /*for (int i = 0; i < *pubkeylen; i++) {
        printf("%02X", (*pubkey)[i]);
    EC_POINT_free(pub);//free all
    BN_CTX_end(ctx);
    BN_CTX_free(ctx);
    BN_clear_free(priv);
    return true;
Just a proof of work,No checks was added.
And I keet rerun the program many times,saw that the program will crash at different code.
Below are some pictures captured when the program crashed.
crashed at EC_KEY_new_by_curve_name
crashed at EC_KEY_set_public_key
crashed on main exit
linked librares
                This does not provide an answer to the question. Once you have sufficient reputation you will be able to comment on any post; instead, provide answers that don't require clarification from the asker.
– Yunnosch
                Oct 5, 2020 at 7:53
                If you intended this to actually be an answer in shape of a rhetoric question please edit to rephrase into a clear statement. Ideally explain how this works and why it is supposed to solve the problem.
– Yunnosch
                Oct 5, 2020 at 7:55
        
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