public:
System::String ^ Replace(System::String ^ oldValue, System::String ^ newValue, bool ignoreCase, System::Globalization::CultureInfo ^ culture);
public string Replace (string oldValue, string? newValue, bool ignoreCase, System.Globalization.CultureInfo? culture);
public string Replace (string oldValue, string newValue, bool ignoreCase, System.Globalization.CultureInfo culture);
member this.Replace : string * string * bool * System.Globalization.CultureInfo -> string
Public Function Replace (oldValue As String, newValue As String, ignoreCase As Boolean, culture As CultureInfo) As String
此方法不修改当前实例的值。 而是返回一个新字符串，其中的所有匹配项
oldValue
都替换为
newValue
。
此方法使用提供的
culture
和
ignoreCase
区分大小写来执行搜索以查找
oldValue
。
由于此方法返回修改后的字符串，因此可以将对 方法的连续调用
Replace
链接在一起，以对原始字符串执行多个替换。 方法调用从左到右执行。 下面的示例进行了这方面的演示。
String s = "aaa";
Console.WriteLine("The initial string: '{0}'", s);
s = s.Replace("a", "b").Replace("b", "c").Replace("c", "d");
Console.WriteLine("The final string: '{0}'", s);
// The example displays the following output:
// The initial string: 'aaa'
// The final string: 'ddd'
let s = "aaa"
printfn $"The initial string: '{s}'"
let s2 = s.Replace("a", "b").Replace("b", "c").Replace("c", "d")
printfn $"The final string: '{s2}'"
// The example displays the following output:
// The initial string: 'aaa'
// The final string: 'ddd'
Module Example
Public Sub Main()
Dim s As String = "aaa"
Console.WriteLine("The initial string: '{0}'", s)
s = s.Replace("a", "b").Replace("b", "c").Replace("c", "d")
Console.WriteLine("The final string: '{0}'", s)
End Sub
End Module
' The example displays the following output:
' The initial string: 'aaa'
' The final string: 'ddd'
public:
System::String ^ Replace(System::String ^ oldValue, System::String ^ newValue, StringComparison comparisonType);
public string Replace (string oldValue, string? newValue, StringComparison comparisonType);
public string Replace (string oldValue, string newValue, StringComparison comparisonType);
member this.Replace : string * string * StringComparison -> string
Public Function Replace (oldValue As String, newValue As String, comparisonType As StringComparison) As String
此方法不修改当前实例的值。 而是返回一个新字符串，其中的所有匹配项
oldValue
都替换为
newValue
。
此方法使用 描述
comparisonType
的区域性和区分大小写来执行搜索以查找
oldValue
。
由于此方法返回修改后的字符串，因此可以将对 方法的连续调用
Replace
链接在一起，以对原始字符串执行多个替换。 方法调用从左到右执行。 下面的示例进行了这方面的演示。
String s = "aaa";
Console.WriteLine("The initial string: '{0}'", s);
s = s.Replace("a", "b").Replace("b", "c").Replace("c", "d");
Console.WriteLine("The final string: '{0}'", s);
// The example displays the following output:
// The initial string: 'aaa'
// The final string: 'ddd'
let s = "aaa"
printfn $"The initial string: '{s}'"
let s2 = s.Replace("a", "b").Replace("b", "c").Replace("c", "d")
printfn $"The final string: '{s2}'"
// The example displays the following output:
// The initial string: 'aaa'
// The final string: 'ddd'
Module Example
Public Sub Main()
Dim s As String = "aaa"
Console.WriteLine("The initial string: '{0}'", s)
s = s.Replace("a", "b").Replace("b", "c").Replace("c", "d")
Console.WriteLine("The final string: '{0}'", s)
End Sub
End Module
' The example displays the following output:
' The initial string: 'aaa'
' The final string: 'ddd'
public:
System::String ^ Replace(System::String ^ oldValue, System::String ^ newValue);
public string Replace (string oldValue, string newValue);
public string Replace (string oldValue, string? newValue);
member this.Replace : string * string -> string
Public Function Replace (oldValue As String, newValue As String) As String
int main()
String^ errString = "This docment uses 3 other docments to docment the docmentation";
Console::WriteLine( "The original string is:\n'{0}'\n", errString );
// Correct the spelling of S"document".
String^ correctString = errString->Replace( "docment", "document" );
Console::WriteLine( "After correcting the string, the result is:\n'{0}'", correctString );
// This code example produces the following output:
// The original string is:
// 'This docment uses 3 other docments to docment the docmentation'
// After correcting the string, the result is:
// 'This document uses 3 other documents to document the documentation'
string errString = "This docment uses 3 other docments to docment the docmentation";
Console.WriteLine("The original string is:{0}'{1}'{0}", Environment.NewLine, errString);
// Correct the spelling of "document".
string correctString = errString.Replace("docment", "document");
Console.WriteLine("After correcting the string, the result is:{0}'{1}'",
Environment.NewLine, correctString);
// This code example produces the following output:
// The original string is:
// 'This docment uses 3 other docments to docment the docmentation'
// After correcting the string, the result is:
// 'This document uses 3 other documents to document the documentation'
open System
let errString = "This docment uses 3 other docments to docment the docmentation"
printfn $"The original string is:{Environment.NewLine}'{errString}'{Environment.NewLine}"
// Correct the spelling of "document".
let correctString = errString.Replace("docment", "document")
printfn $"After correcting the string, the result is:{Environment.NewLine}'{correctString}'"
// This code example produces the following output:
// The original string is:
// 'This docment uses 3 other docments to docment the docmentation'
// After correcting the string, the result is:
// 'This document uses 3 other documents to document the documentation'
Public Class ReplaceTest
Public Shared Sub Main()
Dim errString As String = "This docment uses 3 other docments to docment the docmentation"
Console.WriteLine("The original string is:{0}'{1}'{0}", Environment.NewLine, errString)
' Correct the spelling of "document".
Dim correctString As String = errString.Replace("docment", "document")
Console.WriteLine("After correcting the string, the result is:{0}'{1}'", Environment.NewLine, correctString)
End Sub
End Class
' This code example produces the following output:
' The original string is:
' 'This docment uses 3 other docments to docment the docmentation'
' After correcting the string, the result is:
' 'This document uses 3 other documents to document the documentation'
如果
newValue
为
null
，则删除 的所有
oldValue
匹配项。
此方法不修改当前实例的值。 而是返回一个新字符串，其中的所有匹配项
oldValue
都替换为
newValue
。
此方法执行序号 (区分大小写和不区分区域性的) 搜索来查找
oldValue
。
由于此方法返回修改后的字符串，因此可以将对 方法的连续调用
Replace
链接在一起，以对原始字符串执行多个替换。 方法调用从左到右执行。 下面的示例进行了这方面的演示。
String s = "aaa";
Console.WriteLine("The initial string: '{0}'", s);
s = s.Replace("a", "b").Replace("b", "c").Replace("c", "d");
Console.WriteLine("The final string: '{0}'", s);
// The example displays the following output:
// The initial string: 'aaa'
// The final string: 'ddd'
let s = "aaa"
printfn $"The initial string: '{s}'"
let s2 = s.Replace("a", "b").Replace("b", "c").Replace("c", "d")
printfn $"The final string: '{s2}'"
// The example displays the following output:
// The initial string: 'aaa'
// The final string: 'ddd'
Module Example
Public Sub Main()
Dim s As String = "aaa"
Console.WriteLine("The initial string: '{0}'", s)
s = s.Replace("a", "b").Replace("b", "c").Replace("c", "d")
Console.WriteLine("The final string: '{0}'", s)
End Sub
End Module
' The example displays the following output:
' The initial string: 'aaa'
' The final string: 'ddd'
public:
System::String ^ Replace(char oldChar, char newChar);
public string Replace (char oldChar, char newChar);
member this.Replace : char * char -> string
Public Function Replace (oldChar As Char, newChar As Char) As String
String^ str = "1 2 3 4 5 6 7 8 9";
Console::WriteLine( "Original string: \"{0}\"", str );
Console::WriteLine( "CSV string: \"{0}\"", str->Replace( ' ', ',' ) );
// This example produces the following output:
// Original string: "1 2 3 4 5 6 7 8 9"
// CSV string: "1,2,3,4,5,6,7,8,9"
String str = "1 2 3 4 5 6 7 8 9";
Console.WriteLine("Original string: \"{0}\"", str);
Console.WriteLine("CSV string: \"{0}\"", str.Replace(' ', ','));
// This example produces the following output:
// Original string: "1 2 3 4 5 6 7 8 9"
// CSV string: "1,2,3,4,5,6,7,8,9"
let str = "1 2 3 4 5 6 7 8 9"
printfn $"Original string: \"{str}\""
printfn $"CSV string: \"{str.Replace(' ', ',')}\""
// This example produces the following output:
// Original string: "1 2 3 4 5 6 7 8 9"
// CSV string: "1,2,3,4,5,6,7,8,9"
Class stringReplace1
Public Shared Sub Main()
Dim str As [String] = "1 2 3 4 5 6 7 8 9"
Console.WriteLine("Original string: ""{0}""", str)
Console.WriteLine("CSV string: ""{0}""", str.Replace(" "c, ","c))
End Sub
End Class
' This example produces the following output:
' Original string: "1 2 3 4 5 6 7 8 9"
' CSV string: "1,2,3,4,5,6,7,8,9"
此方法执行序号 (区分大小写和不区分区域性的) 搜索来查找
oldChar
。
此方法不修改当前实例的值。 而是返回一个新字符串，其中的所有匹配项
oldChar
都替换为
newChar
。
由于此方法返回修改后的字符串，因此可以将对 方法的连续调用
Replace
链接在一起，以对原始字符串执行多个替换。 方法调用从左到右执行。 下面的示例进行了这方面的演示。
String s = new String('a', 3);
Console.WriteLine("The initial string: '{0}'", s);
s = s.Replace('a', 'b').Replace('b', 'c').Replace('c', 'd');
Console.WriteLine("The final string: '{0}'", s);
// The example displays the following output:
// The initial string: 'aaa'
// The final string: 'ddd'
let s = new string('a', 3)
printfn $"The initial string: '{s}'"
let s2 = s.Replace('a', 'b').Replace('b', 'c').Replace('c', 'd')
printfn $"The final string: '{s2}'"
// The example displays the following output:
// The initial string: 'aaa'
// The final string: 'ddd'
Module Example
Public Sub Main()
Dim s As New String("a"c, 3)
Console.WriteLine("The initial string: '{0}'", s)
s = s.Replace("a"c, "b"c).Replace("b"c, "c"c).Replace("c"c, "d"c)
Console.WriteLine("The final string: '{0}'", s)
End Sub
End Module
' The example displays the following output:
' The initial string: 'aaa'
' The final string: 'ddd'
