小子在使用mysql的json时,键是数字,按常规方法访问:

SET @j = '{"0": {"a":1, "b":2}, "other": {"c": 3, "d": 4}}';
SELECT JSON_EXTRACT(@j, '$.0.a') AS '$.0.a'

但是报了一个异常:

Invalid JSON path expression. The error is around character position 3.
时间: 0s

查看官方文档,有如下说明:

Names of keys must be double-quoted strings or valid ECMAScript identifiers (see http://www.ecma-international.org/ecma-262/5.1/#sec-7.6). Path expressions, like JSON text, should be encoded using the ascii, utf8, or utf8mb4 character set. Other character encodings are implicitly coerced to utf8mb4.

文档地址:MySQL JSON 官方文档
解决方法:
数字键必须单独使用双引号包围,如下:

SET @j = '{"0": {"a":1, "b":2}, "other": {"c": 3, "d": 4}}';
SELECT JSON_EXTRACT(@j, '$."0".a') AS `$.0.a`;
+-------+
| $.0.a |
+-------+
| 1     |
+-------+
1 row in set (0.00 sec)
                                    The syntax looks right to me, any help would be appreciated!mysql> select fieldnames from tablename limit 5;+--------------------------------------------------------+| fieldnames                   ...
select json_column->'$."key"' from tb where id ='1'
如上sql查询结果value值会带有" "双引号,使用JSON_UNQUOTE()函数即可:
select JSON_UNQUOTE(json_column->'$."key"') from tb w
                                    mysql8.0 JSON_EXTRACT函数获取json中的数据(Invalid JSON path expression. The error is around character position)
                                    java.sql.SQLSyntaxErrorException: Invalid JSON path expression. The error is around character position 5.
	at com.mysql.cj.jdbc.exceptions.SQLError.createSQLException(SQLError.java:120)
	at com.mysql...
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                                    数字键查询报错
SELECT id from cmf_customer WHERE phone->'$.15103825200'= 15103825200
> Invalid JSON path expression. The error is around character position 13.
> 时间: 0.041s
json列内的数字field,必须用英文双引号括起来
SELECT id from cmf_customer WHERE phone->'$."15103
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