获取当前工程resources目录下文件的路径

String fileName = this.getClass().getClassLoader().getResource("文件名").getPath(); //获取文件路径
运行结果：
/D:/work/svnCode/RYZS-Automation/target/classes/5个身份证号.csv
获取当前类所在工程的路径
String property =System.getProperty("user.dir");
运行结果：
D:\work\svnCode\RYZS-Automation
获取当前类所在工程的路径
File directory = new File("");//参数为空
String courseFile = directory.getCanonicalPath() ;
String author =directory.getAbsolutePath();
运行结果：
D:\work\svnCode\RYZS-Automation
D:\work\svnCode\RYZS-Automation
获取当前类的所在工程路径：
File f = new File(this.getClass().getResource("/").getPath()); 
D:\work\svnCode\RYZS-Automation\target\classes
如果不加“/” ，获取当前类的绝对路径：
File f = new File(this.getClass().getResource("").getPath()); 
D:\work\svnCode\RYZS-Automation\target\classes\com\chinal\ryzsAutomation\service
二、获取的路径中文件名中文乱码
        String localFilePath = this.getClass().getClassLoader().getResource("5个身份证号.csv").getPath();
        try {
            localFilePath = URLDecoder.decode(localFilePath, "UTF-8");
            System.out.println(localFilePath);
        } catch (UnsupportedEncodingException e) {
            e.printStackTrace();
Reference

https://blog.csdn.net/dream_broken/article/details/31762807

https://blog.csdn.net/oschina_40188932/article/details/78833754