let Arr=[1,2,3,4,5,6],
    Data=[5,6,7];
   Arr.find(i=>Data.includes(i))
如果有相同项就返回对应的一项，没有相同项，结果是undefined
比如一个数组
arr = [
{hr: [ "System Architect", "$3,120", "2011/04/25" ], office: "Edinburgh", "extn": "5421"}，
{name:'hongyi'}，
[1,2,3]
就先按照这个样例来吧，如果我要获取name的值改怎么写一个函数呢
本人能力有限，写的...
const isContained = (a, b) => {
    // a和b其中一个不是数组，直接返回false
    if (!(a instanceof Array) || !(b instanceof Array)) return false;
    const len = b.length;
    // a的长度小于b的长度，直接返回false
    if (a.length &l
                                    I have a target array ["apple","banana","orange"] , and I want to check if other arrays contain any
function isContained(aa, bb) {
	if(!(aa instanceof Array) || !(bb instanceof Array) || ((aa.length < bb.length))) {
		return false;
	//var aaStr = ...
                                    //是否被包含,是返回true,不是返回false
isContained =(a, b)=>{
    if(!(a instanceof Array) || !(b instanceof Array)) return false;
    if(a.length < b.length) return false;
    var aStr = a.toString();
    for(var