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I have the code below for running a code that uses mongodb in a .sh file. I am running my code in windows but I think these commands are for Linux. I would be very thankful if someone can let me know the equivalent commands in windows.

#!/bin/bash
base_dir="$1"
echo "Starting MongoDB..."
mongodb/bin/mongod --dbpath "$base_dir"/mongodb/data/db > /dev/null & 
sleep 10
echo "Starting Jetty server..."
java -Xmx8g -jar easy_esa.jar 8800 index &
sleep 10
                These look like they are for Windows to me. Specifically, the usage of \   as a path component separator and the usage of drive letters strongly indicate Windows, since the path component separator for Unix-like operating systems is / and the concept of drive letters doesn't even exist.
– Jörg W Mittag
                Dec 22, 2018 at 15:56
                Oh sorry this is for linux but I changed / to \ by myself as it was the only thing I knew about difference of linux and windows!I edit my question
– Goli A
                Dec 22, 2018 at 16:04
                Try start "" /b mongodb/bin/mongod --dbpath "%base_dir%/mongodb/data/db" <NUL >NUL. This redirects stdin and stdout to NUL. The /b prevents the child from allocating a new console. This has two immediate consequences. stderr will still write to the console unless also redirected; the program can block while writing if the console is in edit mode (e.g. from an errant mouse click if quick-edit mode is enabled). Closing the console sends the process a control-close event, with no more than 5 seconds to handle the event before termination.
– Eryk Sun
                Dec 22, 2018 at 18:06
For Windows to run program in background is a bit diffeent. The best way is to set it up as service. Here is short manual how to create service from program.
Step One: Install SrvStart
Step Two: Create a Configuration File for the New Service
Step Three: Use the Command Prompt to Create the New Service
/dev/null in Windows is NUL: so your command will become:
command parameters > NUL:
        
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