去除一个ArrayList的重复元素有两种方法:( ArrayList与Vector的存储结构是Object[],LinkedList是双向列表 )

第一种是不需要借助临时list，用equals方法比较ArrayList中数据，两次遍历原来list;

第二种是借助一个临时ArrayList,向临时List添加数据，调用arrayList.contains(obj)判断是否存在

了解ArrayList的contains原理:调用obj的equals方法进行判断在ArrayList中的位置是否大于零，进而判断是否存在。

    public boolean contains(Object o) {
        return indexOf(o) >= 0;
     * Returns the index of the first occurrence of the specified element
     * in this list, or -1 if this list does not contain the element.
     * More formally, returns the lowest index <tt>i</tt> such that
     * <tt>(o==null&nbsp;?&nbsp;get(i)==null&nbsp;:&nbsp;o.equals(get(i)))</tt>,
     * or -1 if there is no such index.
    public int indexOf(Object o) {
        if (o == null) {
            for (int i = 0; i < size; i++)
                if (elementData[i]==null)
                    return i;
        } else {
            for (int i = 0; i < size; i++)
                if (o.equals(elementData[i]))
                    return i;
        return -1;
1.　　两种方式对ArrayList中重复字符串的处理:

@Test
    // 第一种去重复方法
    public void Test1() {
        List<String> list = new ArrayList<String>();
        list.add("1");
        list.add("2");
        list.add("3");
        list.add("4");
        list.add("4");
        list.add("3");
        list.add("2");
        list.add("1");
        System.out.println("去重复元素之前:");
        for (String s : list) {
            System.out.println(s);
        // 遍历ArrayList
        for (int i = 0; i < list.size() - 1; i++) {
            for (int j = i + 1; j < list.size(); j++) {
                if (list.get(i).equals(list.get(j))) {
                    list.remove(j);
        System.out.println(list.size());
        System.out.println("去重复元素之后:");
        for (String s : list) {
            System.out.println(s);
    @Test
    // 第二种去重复方法
    public void Test2() {
        List<String> list = new ArrayList<String>();
        list.add("1");
        list.add("2");
        list.add("3");
        list.add("4");
        list.add("4");
        list.add("3");
        list.add("2");
        list.add("1");
        List<String> temp = new ArrayList<String>();
        Iterator<String> iterator = list.iterator();
        while (iterator.hasNext()) {
            String str = iterator.next();
            if (!temp.contains(str)) {
                temp.add(str);
        for (String s : temp) {
            System.out.println(s);
2.　　两种方式对ArrayList中重复对象的处理:
Person.java 　　重写equals方法
package cn.xm.exam.test.javaTest;
import static org.hamcrest.CoreMatchers.instanceOf;
public class Person {
    private String name;
    private String id;
    public String getName() {
        return name;
    public void setName(String name) {
        this.name = name;
    public String getId() {
        return id;
    public void setId(String id) {
        this.id = id;
    public Person(String name, String id) {
        super();
        this.name = name;
        this.id = id;
    // 重写一个Bean的hashCode方法
     * @Override public int hashCode() { // TODO Auto-generated method stub
     * return this.name.hashCode()+this.id.hashCode(); }
    @Override
    public boolean equals(Object obj) {
        if (this == obj) {
            return true;
        if (!(obj instanceof Person)) {
            throw new ClassCastException();// 类型错误
        Person pp = (Person) obj;
        return this.getId().equals(pp.getId()) && this.getName().equals(pp.getName());
    @Override
    public String toString() {
        return "Person [name=" + name + ", id=" + id + "]";
去重算法:
@Test
    // 第一种去重复方法去除Object重复的
    public void Test3() {
        List<Person> list = new ArrayList<Person>();
        list.add(new Person("张三", "1"));
        list.add(new Person("张三", "2"));
        list.add(new Person("张三", "3"));
        list.add(new Person("张三", "4"));
        list.add(new Person("李四", "1"));
        list.add(new Person("李四", "2"));
        list.add(new Person("张三", "1"));
        list.add(new Person("李四", "1"));
        // 遍历ArrayList
        for (int i = 0; i < list.size() - 1; i++) {
            for (int j = i + 1; j < list.size(); j++) {
                if (list.get(i).equals(list.get(j))) {
                    list.remove(j);
        for (Person p : list) {
            System.out.println(p);
    @Test
    // 第二种去重复方法去除Object重复的
    public void Test4() {
        List<Person> list = new ArrayList<Person>();
        list.add(new Person("张三", "1"));
        list.add(new Person("张三", "2"));
        list.add(new Person("张三", "3"));
        list.add(new Person("张三", "4"));
        list.add(new Person("李四", "1"));
        list.add(new Person("李四", "2"));
        list.add(new Person("张三", "1"));
        list.add(new Person("李四", "1"));
        List<Person> temp = new ArrayList<Person>();
        Iterator<Person> iterator = list.iterator();
        while (iterator.hasNext()) {
            Person person = iterator.next();
            if (!temp.contains(person)) {
                temp.add(person);
        for (Person p : temp) {
            System.out.println(p);
Person [name=张三, id=1]
Person [name=张三, id=2]
Person [name=张三, id=3]
Person [name=张三, id=4]
Person [name=李四, id=1]
Person [name=李四, id=2]