import
java.text.ParseException;
import
java.text.SimpleDateFormat;
import
java.util.Calendar;
import
java.util.Date;
public
class
Test {
public
static
void
main(String[] args)
throws
ParseException {
String format
= "HH:mm:ss"
;
Date nowTime
=
new
SimpleDateFormat(format).parse("09:27:00"
);
Date startTime
=
new
SimpleDateFormat(format).parse("09:27:00"
);
Date endTime
=
new
SimpleDateFormat(format).parse("09:27:59"
);
System.out.println(isEffectiveDate(nowTime, startTime, endTime));
* 判断当前时间是否在[startTime, endTime]区间，注意时间格式要一致
*
@param
nowTime 当前时间
*
@param
startTime 开始时间
*
@param
endTime 结束时间
*
@return
*
@author
jqlin
public
static
boolean
isEffectiveDate(Date nowTime, Date startTime, Date endTime) {
if
(nowTime.getTime() ==
startTime.getTime()
|| nowTime.getTime() ==
endTime.getTime()) {
return
true
;
Calendar date
=
Calendar.getInstance();
date.setTime(nowTime);
Calendar begin
=
Calendar.getInstance();
begin.setTime(startTime);
Calendar end
=
Calendar.getInstance();
end.setTime(endTime);
if
(date.after(begin) &&
date.before(end)) {
return
true
;
}
else
{
return
false
;
JAVA8：
//构造时间 00:20:55
LocalTime time1 = LocalTime.of(8,20,55);
LocalTime time3 = LocalTime.of(15,20,55);
LocalTime time4 = LocalTime.of(18,10,55);
if (time1.isBefore(time3) && time4.isAfter(time3)){
System.out.println("在时间区间之内！");
