问 如何使用Selenium和Python访问多个shadowRoot中嵌套的html

innerHTML 的所需信息区间在多个 #阴影-根(打开) 中。

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解决方案

要提取需要使用 shadowRoot.querySelectorAll() 的信息，可以使用以下 定位器策略

• 代码块： Driver.get( https://www.powerlanguage.co.uk/wordle/" ) time.sleep(1) sends=driver.find_element(By.XPATH )"/html/body") sends.click() sends.send_keys("adieu") sends.send_keys(Keys.ENTER) inner_texts = [my_elem.get_attribute("outerHTML") for my_elem in driver.execute_script(“返回inner_text in inner_texts: print(inner_text) )
• 控制台输出：

参考文献

您可以在以下几个方面找到相关的讨论：

• 无法使用Python Selenium在阴影根(打开)中定位
• 如何通过使用Python和Selenium的cookie协议页面？

如果您正在寻找一个完整的Python解决方案，以编程方式解决Wordle游戏，那么这里有一个使用 SeleniumBase 框架的解决方案。该解决方案附带了一个YouTube视频： 用SeleniumBase求解Wordle ，以及 解决方案的Python代码 ，以及一个GIF：

代码使用特殊的SeleniumBase ::shadow 选择器来穿透多层Shadow-DOM。下面的代码可以在调用 pip install seleniumbase 以获取所有Python依赖项之后运行：

import ast
import random
import requests
from seleniumbase import __version__
from seleniumbase import BaseCase
class WordleTests(BaseCase):
    word_list = []
    def initalize_word_list(self):
        js_file = "https://www.powerlanguage.co.uk/wordle/main.e65ce0a5.js"
        req_text = requests.get(js_file).text
        start = req_text.find("var La=") + len("var La=")
        end = req_text.find("],", start) + 1
        word_string = req_text[start:end]
        self.word_list = ast.literal_eval(word_string)
    def modify_word_list(self, word, letter_status):
        new_word_list = []
        correct_letters = []
        present_letters = []
        for i in range(len(word)):
            if letter_status[i] == "correct":
                correct_letters.append(word[i])
                for w in self.word_list:
                    if w[i] == word[i]:
                        new_word_list.append(w)
                self.word_list = new_word_list
                new_word_list = []
        for i in range(len(word)):
            if letter_status[i] == "present":
                present_letters.append(word[i])
                for w in self.word_list:
                    if word[i] in w and word[i] != w[i]:
                        new_word_list.append(w)
                self.word_list = new_word_list
                new_word_list = []
        for i in range(len(word)):
                letter_status[i] == "absent"
                and word[i] not in correct_letters
                and word[i] not in present_letters
                for w in self.word_list:
                    if word[i] not in w:
                        new_word_list.append(w)
                self.word_list = new_word_list
                new_word_list = []
    def test_wordle(self):
        self.open("https://www.powerlanguage.co.uk/wordle/")
        self.click("game-app::shadow game-modal::shadow game-icon")
        self.initalize_word_list()
        keyboard_base = "game-app::shadow game-keyboard::shadow "
        word = random.choice(self.word_list)
        total_attempts = 0
        success = False
        for attempt in range(6):
            total_attempts += 1
            word = random.choice(self.word_list)
            letters = []
            for letter in word:
                letters.append(letter)
                button = 'button[data-key="%s"]' % letter
                self.click(keyboard_base + button)
            button = 'button[data-key="↵"]'
            self.click(keyboard_base + button)
            self.sleep(1)  # Time for the animation
            row = 'game-app::shadow game-row[letters="%s"]::shadow ' % word
            tile = row + "game-tile:nth-of-type(%s)"
            letter_status = []
            for i in range(1, 6):
                letter_eval = self.get_attribute(tile % str(i), "evaluation")
                letter_status.append(letter_eval)
            if letter_status.count("correct") == 5:
                success = True
                break
            self.word_list.remove(word)
            self.modify_word_list(word, letter_status)