var b ={"c":"3","d":"4","e":"5"}
var c = $.extend({}, a,b);
console.log(c);//输出结果，{"a":"1","b":"2","c":"3","d":"4","e":"5"}
调用ajax在给后台传参数的时候，如何把2个json合并成一个json:这里用到 $.extend()方法此处引用jQuery库，请记得先加载jquery var a ={"a":"1","b":"2"} var b ={"c":"3","d":"4","e":"5"} var c = $.extend({}, a,b); console.log(c);//输出结果，{"a
@Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
var arr = [
{“id”:“1001”,“name”:“值1”,“value”:“111”},
{“id”:“1001”,“name”:“值1”,“value”:“11111”},
{“id”:“1002”,“name”:“值2”,“value”:“25462”},
{“id”:“1002”,“name”:“值2”,“value”:“23131”},
{“id”:“1002”,“name...
var dataParams = {};
var datasourceParam = datasource_param; //数据源，根据不同的数据表可变
var unitTimeParam = "unit_time"; //取值方式
var limitParam = "limit"; //取值数量
var timeMinParam = "time_min...
我们使用
ajax
通常传递的是
json
对象
，但是我们如果需要同时传递
两个
对象
到后台时怎么办？
如：我们后台同时需要分页信息Pages，和查询图书的条件信息Books，我们可以创建
一个
类关联这
两个
类：
public class PageBooks {
private Pages PageBooks_pages;
private Books PageBooks_books;
