如何删除Python字典列表中的值中的特殊字符？

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我想把所有的'/api/1/employees/'和/api/1/seats/从python词典中删除。最简单的方法是什么。我的字典目前看起来是这样的 -

dict1 = {5051: ['/api/1/employees/4027', '5051', '/api/1/seats/19014'], 5052: ['/api/1/employees/4048', '5052', '/api/1/seats/19013'], 5053: ['/api/1/employees/4117', '5053', '/api/1/seats/19012'], 5054: ['/api/1/employees/15027', '5054', '/api/1/seats/9765']}
我期待着以下的决定
dict1 = {5051: ['4027', '5051', '19014'], 5052: ['4048', '5052', '19013'], 5053: ['4117', '5053', '19012'], 5054: ['15027', '5054', '9765']}


           
            
             Danish Bansal
            
            ：


           
            
             是否有可能在最后有一个"/"？


           
            
             请提供足够的代码，以便其他人能够更好地理解或重现这个问题。


         
          python


         
          dictionary


          
           
            
            
             user2390182
            
           
           
            发布于
            
            2021-09-23


          
           已采纳


          
           
            Use
            
             
              str.rsplit
             
            
            :
           
           dict1 = {k: [s.rsplit("/", 1)[-1] for s in v] for k, v in dict1.items()}


          
           
            
             下面的方法可行。我们的想法是尝试将条目转换为
             
              int
             
             ，如果我们失败了--分割条目并返回最后一个元素
            
            data = {5051: ['/api/1/employees/4027', '5051', '/api/1/seats/19014'],
         5052: ['/api/1/employees/4048', '5052', '/api/1/seats/19013'],
         5053: ['/api/1/employees/4117', '5053', '/api/1/seats/19012'],
         5054: ['/api/1/employees/15027', '5054', '/api/1/seats/9765']}
def get_int(value):
        x = int(value)
        return value
    except ValueError:
        return value.split('/')[-1]
data = {k: [get_int(vv) for vv in v] for k,v in data.items()}
print(data)
output
{5051: ['4027', '5051', '19014'], 5052: ['4048', '5052', '19013'], 5053: ['4117', '5053', '19012'], 5054: ['15027', '5054', '9765']}


          
           
            
             
              
               
               
                Danish Bansal
               
              
              
               发布于
               
               2021-09-23


          
           
            
             
              
               使用下面的重码词
              
              import re
regex = r"[0-9][0-9]+"
dict1 = {5051: ['/api/1/employees/4027', '5051', '/api/1/seats/19014'],
         5052: ['/api/1/employees/4048', '5052', '/api/1/seats/19013'],
         5053: ['/api/1/employees/4117', '5053', '/api/1/seats/19012'],
         5054: ['/api/1/employees/15027', '5054', '/api/1/seats/9765']}
for i in dict1:
    dict1[i] = [re.findall(regex, j)[0] if len(re.findall(regex, j)) >= 1 else j for j in dict1[i]]
print(dict1)