六方晶系FFT斑点标定求助已有1人参与

各位大神,本人透射小白,最近做了一组高分辨率,对其中的A区进行FFT变换后得到相应的斑点,对斑点进行标定时,发现有好几套晶面指数都可以对应上,瞬间就惊呆了,按照常理,应该只有一套斑点对应,这个是怎么回事,望高人指点,在此谢过!金币不多,还望见谅!

高分辨率材料为钛,A区的基体为密排六方基本的参数如下:

Crystal Structures 1 (1963) 7-83
Second edition. Interscience Publishers, New York, New York
Hexagonal closest packed, hcp, structure
_database_code_amcsd 0011195
2.950 2.950 4.686 90 90 120 P6_3/mmc
atom x y z
Ti 1/3 2/3 .25
测得R1=0.447nm,R2=0.2503nm,R3=0.2231nm, =90, =60, =30

计算的晶面指数分别对应:R1:(010)(-110)及(100); R2:(0-11)(1-11)(-101)(011)(-111)(101) R3001)
根据晶面间距、角度关系及R1+R2=R3可以确定的指数有1:R1(-110)R2(-111)R3(001) 2:R1(100)R2(101)R3(001) 等若干组。相应的图表见附件,望高人指点!

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