在pyqt5 /Python3中，当主GUI窗口关闭时，如何使子线程关闭？

from PyQt5 import QtWidgets
from PyQt5.QtWidgets import (QWidget, QApplication,QPushButton, 
                             QVBoxLayout)
import time, threading, sys
class testScriptApp(QtWidgets.QWidget):
    def __init__(self, parent=None):
        # initialize th widget
        QtWidgets.QWidget.__init__(self, parent)
        # set the window title
        self.setWindowTitle("Scripting")
        # manage the layout
        self.mainGrid = QVBoxLayout()
        self.button = QPushButton('Start')
        self.button.clicked.connect(self.on_click)
        self.mainGrid.addWidget(self.button)
        self.setLayout(self.mainGrid)
    def on_click(self):
        self.worker = threading.Thread(target=Worker)
        self.worker.daemon = True
        self.worker.start()
def Worker(count=1):
    while count>0:
        print(count)
        time.sleep(2)
        count+=1
if __name__ == "__main__":
    app = QtWidgets.QApplication(sys.argv)
    myapp = testScriptApp()
    myapp.show()
    app.exec_()

from PyQt5 import QtWidgets
from PyQt5.QtWidgets import (QWidget, QApplication,QPushButton, 
                             QVBoxLayout)
from PyQt5.QtCore import QThread
import time, threading, sys
class testScriptApp(QtWidgets.QWidget):
    def __init__(self, parent=None):
        # initialize th widget
        QtWidgets.QWidget.__init__(self, parent)
        # set the window title
        self.setWindowTitle("Scripting")
        # manage the layout
        self.mainGrid = QVBoxLayout()
        self.button = QPushButton('Start')
        self.button.clicked.connect(self.on_click)
        self.mainGrid.addWidget(self.button)
        self.setLayout(self.mainGrid)
    def on_click(self):
        self.worker = Worker()
        self.worker.run()
    def closeEvent(self,event):
        print('Closing')
        self.worker.terminate()
        event.accept()
class Worker(QThread):
    def __init__(self):
        QThread.__init__(self)
    def run(self):
        count=1
        while count>0:
            print(count)
            time.sleep(2)
            count+=1
if __name__ == "__main__":
    app = QtWidgets.QApplication(sys.argv)
    myapp = testScriptApp()
    myapp.show()
    app.exec_()

from PyQt5 import QtWidgets
from PyQt5.QtWidgets import (QWidget, QApplication,QPushButton, 
                             QVBoxLayout)
from PyQt5.QtCore import QThread,QObject
import time, threading, sys
class testScriptApp(QtWidgets.QWidget):
    def __init__(self, parent=None):
        # initialize th widget
        QtWidgets.QWidget.__init__(self, parent)
        # set the window title
        self.setWindowTitle("Scripting")
        # manage the layout
        self.mainGrid = QVBoxLayout()
        self.button = QPushButton('Start')
        self.button.clicked.connect(self.on_click)
        self.mainGrid.addWidget(self.button)
        self.setLayout(self.mainGrid)
    def on_click(self):
        self.my_thread = QThread()
        self.worker = Worker()
        self.worker.moveToThread(self.my_thread)
        self.my_thread.started.connect(self.worker.run)
        self.my_thread.start()        
    def closeEvent(self,event):
        print('Closing')
class Worker(QObject):
    def __init__(self):
        super().__init__()
    def run(self):
        count=1
        while count>0:
            print(count)
            time.sleep(2)
            count+=1

在pyqt5 /Python3中，当主GUI窗口关闭时，如何使子线程关闭？

2 个回答