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Try the decodeURIComponent function:

var decodedUri = decodeURIComponent('http%3A%2F%2Fdtzhqpwfdzscm.cloudfront.net%2F4ca06373624db.jpg');
alert(decodedUri);
                But that doesn't use jQuery (and please don't link to W3Schools, they are good at SEO and poor at teaching correct information)!
– Quentin
                Sep 27, 2010 at 12:38
                Well I dont see the point to use jQuery when a native javascript function can do it. And what's matter about W3Schools? is not a place where you are going to ask a COMPLEX specific question about programming but at least works as reference or introduction for an general problem. I don't see any bad with that.
– ncubica
                Mar 11, 2012 at 1:30
                @nahum W3C (World Wide Web Consortium) is actually a very good place to get the right information. w3schools, who has NOTHING to do with W3C, isn't. I assume you know the difference between them and that it was just a typo. However, you just demonstrated why they choosed that name and how easy it is to get it mixed up. If you want to continue using them, even though you know that the information they have is misleading  or wrong, instead of using something that is easily accessible and with better information, no one will stop you. But you will get complaints when you publicly link to them.
– some
                Mar 31, 2013 at 7:56
                @AdriánSalgado, why looking for a function in jQuery when this function already exists in plain javascript? I mean that would be like reinventing the wheel, wouldn't it? Check that out: i.stack.imgur.com/ssRUr.gif
– Darin Dimitrov
                Feb 25, 2014 at 22:57
Use decodeURIComponent(), for example:
decodeURIComponent("http%3A%2F%2Fdtzhqpwfdzscm.cloudfront.net%2F4ca06373624db.jpg")
It's not jQuery specific, this is a base JavaScript function.
You can simply call the standard javascript functions for encoding and decoding respectively.
encodeURIComponent
decodeURIComponent
Enjoy!
If you URL should also contain blanks encoded as '+', the following call will help (taken from https://stackoverflow.com/a/4458580/430742):
decodeURIComponent((str+'').replace(/\+/g, '%20'))
        
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