在Linux中使用curl命令（Shell脚本）从URL下载多个文件到一个特定的路径。

for i in $(curl http://sometimesdownload.com/list_of_files | jq -c '.[]'); then
    # GET file
    curl -O --output-dir /tmp/downloaded_files http://sometimesdownload.com/"$i"
    # DELETE file
    # However this is mostly not working straightforward and need tuning 
    # as no enough information here about how the files are hosted and 
    # configured by the remote server 
    curl -X DELETE http://sometimesdownload.com/"$i"
替换代码1】是jq中的紧凑输出选项，从json数组中获得计划文本输出。
$ echo '["file1.csv","file2.csv","file3.csv"]' | jq -c '.[]'
"file1.csv"
"file2.csv"
"file3.csv"


          
           
            你可以使用下面的脚本。由于列表的语法在BASH中是不同的，你必须转换为BASH语法。[abc,bca] 到 (abc bca)
           
           
            然后你可以一个一个地去扔文件，通过CURL下载。
           
           
            这里是脚本的例子，我相信你可以根据你的环境来修正它。
           
           bashParse() {
    listData=$1
    #validateData
    finalData=()
    echo ${listData} | grep ^"\[" > /dev/null && beginScope=0 || beginScope=1
    echo ${listData} | grep "\]$" > /dev/null && endScope=0   || endScope=1
    # build our List BASH stntax    
    if [ $beginScope -eq 0 ] && [ $endScope -eq 0 ] ; then
        # Here I will remove [ and ], also replace last SPACE with nothing => sed
        declare -a finalData=($(echo $listData|tr '\"' ' '| tr -d '[]'| tr ',' ' '))
    # Download files one by one by CURL
    for i in "${finalData[@]}" ; do
       echo "curl://<link>/$i"