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In my
FragmentLayout
I have a
LinearLayout
with multiple subviews (
TextView
,
CardView
). I want to find the top offset of all
LinearLayout
views but I always get zero.
This is my code:
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
view = inflater.inflate(R.layout.fragment_detail, container, false);
nestedScrollView = (NestedScrollView) view.findViewById(R.id.nestedScrollView);
linearLayout = (LinearLayout) view.findViewById(R.id.lll);
int childCount = linearLayout.getChildCount();
int[] location = new int[2];
for (int i = 0; i < childCount; i++) {
View v = linearLayout.getChildAt(i);
v.getLocationOnScreen(location);
Log.e("locX", location[0] + "");
Log.e("locY", location[1] + "");
return view;
And this is my layout xml :
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout
android:layout_width="match_parent"
android:layout_height="match_parent">
<android.support.design.widget.CoordinatorLayout>
<android.support.design.widget.AppBarLayout>
<android.support.design.widget.CollapsingToolbarLayout>
</android.support.design.widget.CollapsingToolbarLayout>
</android.support.design.widget.AppBarLayout>
<android.support.v4.widget.NestedScrollView
android:id="@+id/nestedScrollView"
android:layout_width="match_parent"
android:layout_height="match_parent"
app:layout_behavior="@string/appbar_scrolling_view_behavior">
<LinearLayout android:id="@+id/lll">
// views are there
</LinearLayout>
</android.support.v4.widget.NestedScrollView>
</android.support.design.widget.CoordinatorLayout>
</LinearLayout>
–
Your screen is not ready when you call onCreate(). To get all the data of the screen you need to wait until it is fully finished. You can use:
your_main_layout_here.getViewTreeObserver().addOnGlobalLayoutListener(new ViewTreeObserver.OnGlobalLayoutListener() {
@Override
public void onGlobalLayout() {
// Remove the Global observer once it is called
your_main_layout_here.getViewTreeObserver().removeOnGlobalLayoutListener(this);
// Your code here, i.e. check the view's location
And then
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