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I'm trying to convert each letter in a string to it's ASCII number. Using
int letter = (atoi(ptext[i]));
gives me this error:
error: incompatible integer to pointer conversion
passing 'char' to parameter of type 'const char *'; take the
address with & [-Werror]
int letter = (atoi(ptext[i]));
^~~~~~~~
/usr/include/stdlib.h:148:32: note: passing argument to parameter
'__nptr' here
extern int atoi (__const char *__nptr)
Here is some of the rest of my code that may be relevant:
#include <cs50.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>
int main(int argc, string argv[])
printf("Give a string to cipher:\n");
string ptext = GetString();
int i = 0;
if (isupper(ptext[i]))
int letter = (atoi(ptext[i]));
What am I doing wrong, and how do I fix this so I can convert a string into ASCII values?
Note: cs50.h lets me use "string" instead of "char*" in main.
atoi() expects a string. You only want the char code of the character... which is the character itself, since in C, the char is a normal integer type just like every other integer, and a string is an array of chars which hold the character codes themselves.
Consequently,
int letter = ptext[i];
would do the job.
You do not need to convert characters to a number. It is a matter of interpretation of your data.
Charater 'A' can be thought of 0x41 or 65 so this is perfectly fine:
int number = 'A';
and value on variable number is 0x41/65 or 1000001b depending how you want to present it/treat it.
As for interpretation : 0xFF may be treated as 255 if you present it as unsigned value or even as -1 when treated as signed and kept in 8 bits.
So your question:
can convert a string into ASCII values?
is kind of wrong - all characters of the string are already ascii values - it is just a matter of how you treat/print/interpret/present them.
atoi() convert string to integer not character.
To store ascii value of character into integer variable Do direct assignment of character to integer variable.
int letter = ptext[i];
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