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<script type="text/javascript" src="jquery-1.6.1.js"></script>
<script type="text/javascript">
$(document).ready( function() {
$('#prev').click(function() {
$.ajax({
type: 'POST',
url: 'ajax.php',
data: 'id=testdata',
cache: false,
success: function(result) {
$('#content1').html(result[0]);
</script>
</head>
<table>
<td id="prev">prev</td>
<td id="content1">X</td>
<td id="next">next</td>
</table>
</body>
and a php file
ajax.php
to handle ajax requests as;
$array = array(1,2,3,4,5,6);
echo $array;
But when I click, I am getting
A
instead of array[0]. How can I fix this?
$change = array('key1' => $var1, 'key2' => $var2, 'key3' => $var3);
echo json_encode(change);
Then the jquery script ...
<script>
$.get("location.php", function(data){
var duce = jQuery.parseJSON(data);
var art1 = duce.key1;
var art2 = duce.key2;
var art3 = duce.key3;
</script>
–
–
When you echo $array;, the result is Array, result[0] then represents the first character in Array which is A.
One way to handle this problem would be like this:
ajax.php
$array = array(1,2,3,4,5,6);
foreach($array as $a)
echo $a.",";
jquery code
$(function(){ /* short for $(document).ready(function(){ */
$('#prev').click(function(){
$.ajax({type: 'POST',
url: 'ajax.php',
data: 'id=testdata',
cache: false,
success: function(data){
var tmp = data.split(",");
$('#content1').html(tmp[0]);
When you do echo $array;, PHP will simply echo 'Array' since it can't convert an array to a string. So The 'A' that you are actually getting is the first letter of Array, which is correct.
You might actually need
echo json_encode($array);
This should get you what you want.
EDIT : And obviously, you'd need to change your JS to work with JSON instead of just text (as pointed out by @genesis)
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