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I created this function to make the button do a sound when i click it, the sound file is mp3 located in raw/button_click.mp3 directory .

fun play_sound(which_one:Int) {
    if(which_one == 1){
        val mediaPlayer:MediaPlayer? = MediaPlayer.create(Context,R.raw.button_click)
        mediaPlayer?.start()
But i get the following error when i run it Unresolved reference: Context
How should I edit my code to solve this problem?
By the way just ignore the if statement for now it always turns true for this stage of development.
Unresolved reference: Context
You receive the following error because you are using the Class instead of your variable name as parameter.
fun play_sound(which_one:Int) {
    if(which_one == 1) {
        val mediaPlayer:MediaPlayer? = MediaPlayer.create(Context,R.raw.button_click)
        mediaPlayer?.start()
There are also different kind of Contexts in Android.
You have your Application, Activity, and Fragment Context, which is also tied to different lifecycles depending on what Context you used.
If this function is a member of your Activity.
fun play_sound(which_one:Int) {
    if(which_one == 1) {
        val mediaPlayer:MediaPlayer? = MediaPlayer.create(this@YourActivityHere,R.raw.button_click)
        mediaPlayer?.start()
Fragment
fun play_sound(which_one:Int) {
    if(which_one == 1) {
        val mediaPlayer:MediaPlayer? = MediaPlayer.create(requireContext(),R.raw.button_click)
        mediaPlayer?.start()
pass proper active Context to this method
fun play_sound(ctx:Context, which_one:Int) {
    if(which_one == 1){
        val mediaPlayer:MediaPlayer? = MediaPlayer.create(ctx, R.raw.button_click)
        mediaPlayer?.start()
                if you start this method from Activity then you may pass this as Activity IS a Context instance (extends it)
– snachmsm
                Nov 5, 2020 at 21:20
        
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