#include<iostream>
#include<string>
#include<fstream>
#include<ctime>
using namespace std;
int a[26]={0};
int getLength(char *p)
{
int i=0;
while(*p!='/0')
{
i++;
p++;
}
return i;
}
void stat(char *pt)
{
while(*pt!='/0')//a对应a[0],b对应a[1]...
{
char b=*pt;
a[b-'a']++;
pt++;
}
}
int compare(char * p1,char * p2)
{
if(*p1==*p2)
return 1;
else
return 0;
}
void main()
{
time_t start=clock();
//char s1[]="faifdanfarjioafjadffarefafafaf";
//char s2[]="faifdanfarjioafcdfefafafafialo";
char s1[1000];
char s2[1000];
char*p,*t;
ifstream infile("D://VCSun//BitChar//data.txt",ios::in);
ofstream outfile("D://VCSun//BitChar//result.txt");
int n=0;
bool flag=1;
for(;;)
{
//cout<<"......"<<m<<endl;
char a;
if(!infile.eof())
{
infile>>a;
//outfile<<a;
if(a==';')
{
flag=0;s1[n]='/0';n=0;continue;
}
if(flag)
{
s1[n]=a;
//outfile<<s1[n]<<endl;
n++;
//cout<<n<<endl;
}
else
{
s2[n]=a;
//outfile<<s2[n];
n++;
//cout<<n<<endl;
}
}
else
{
s2[n-1]='/0';//最后判断多执行了一次
break;
}
}
int same=0,diff=0;//相同的个数及不同个数
for(p=s1,t=s2;*p!='/0',*t!='/0';p++,t++)
{
outfile<<*p<<" "<<*t<<endl;
if(compare(p,t))
same++;
else
diff++;
}
infile.close();
outfile.close();
//cout<<s1<<endl;
//cout<<s2<<endl;
cout<<"相同的个数为"<<same<<"个！"<<endl;
cout<<"不同的个数为"<<diff<<"个！"<<endl;
time_t end=clock();
double dur=static_cast<double>(end-start)/CLOCKS_PER_SEC*1000;
cout<<"/n您的程序执行所耗费的时间为:"<<dur<<"毫秒。"<<endl;
p=s2;
stat(p);
//char s='d';
//int c=s-'a';
//cout<<"........."<<c<<endl;
int sum=0;
for(int i=0;i<26;i++)
{
cout<<char('a'+i)<<"个数为"<<a[i]<<"."<<endl;
sum=sum+a[i];
}
cout<<sum<<endl;
int summ=getLength(p);
cout<<summ<<endl;
}
<br />#include<iostream><br />#include<string><br />#include<fstream><br />#include<ctime><br />using namespace std;<br />int a[26]={0};<br />int getLength(char *p)<br />{<br /> int i=0;<br /> while(*p!='/0')<br /> {<br />
for(int dex = 0 ; dex < strSource.GetLength() ; ++ dex)
CString str = strUser.Mid(dex , 1);
if(strSource....
def count_error(text1,text2):
text1_lines = text1.splitlines()
text2_lines = text2.splitlines()
d = difflib.Differ()
diff = d.co...
