Collectives™ on Stack Overflow
Find centralized, trusted content and collaborate around the technologies you use most.
Learn more about Collectives
Teams
Q&A for work
Connect and share knowledge within a single location that is structured and easy to search.
Learn more about Teams
I seem to be having issues pushing data into a state array.
I am trying to achieve it this way:
this.setState({ myArray: this.state.myArray.push('new value') })
But I believe this is incorrect way and causes issues with mutability?
–
Using es6 it can be done like this:
this.setState({ myArray: [...this.state.myArray, 'new value'] }) //simple value
this.setState({ myArray: [...this.state.myArray, ...[1,2,3] ] }) //another array
Spread syntax
–
–
–
–
–
Array push returns length
this.state.myArray.push('new value')
returns the length of the extended array, instead of the array itself.Array.prototype.push().
I guess you expect the returned value to be the array.
Immutability
It seems it's rather the behaviour of React:
NEVER mutate this.state directly, as calling setState() afterwards may
replace the mutation you made. Treat this.state as if it were
immutable.React.Component.
I guess, you would do it like this (not familiar with React):
var joined = this.state.myArray.concat('new value');
this.setState({ myArray: joined })
–
–
–
–
–
–
The recommended approach in later React versions is to use an updater function when modifying states to prevent race conditions:
Push string to end of the array
this.setState(prevState => ({
myArray: [...prevState.myArray, "new value"]
Push string to beginning of the array
this.setState(prevState => ({
myArray: ["new value", ...prevState.myArray]
Push object to end of the array
this.setState(prevState => ({
myArray: [...prevState.myArray, {"name": "object"}]
Push object to beginning of the array
this.setState(prevState => ({
myArray: [ {"name": "object"}, ...prevState.myArray]
–
–
–
–
You should not be operating the state at all. At least, not directly. If you want to update your array, you'll want to do something like this.
var newStateArray = this.state.myArray.slice();
newStateArray.push('new value');
this.setState(myArray: newStateArray);
Working on the state object directly is not desirable. You can also take a look at React's immutability helpers.
https://facebook.github.io/react/docs/update.html
–
Here you can not push the object to a state array like this. You can push like your way in normal array.
Here you have to set the state,
this.setState({
myArray: [...this.state.myArray, 'new value']
You can use .concat
method to create copy of your array with new data:
this.setState({ myArray: this.state.myArray.concat('new value') })
But beware of special behaviour of .concat
method when passing arrays - [1, 2].concat(['foo', 3], 'bar')
will result in [1, 2, 'foo', 3, 'bar']
.
Using react hooks, you can do following way
const [countryList, setCountries] = useState([]);
setCountries((countryList) => [
...countryList,
"India",
–
.then(response => response.json())
.then(json => {
this.setState({mystate: this.state.mystate.push.apply(this.state.mystate, json)})
–
–
–
React-Native
if u also want ur UI (ie. ur flatList) to be up to date, use PrevState:
in the example below if user clicks on the button , it is going to add a new object to the list( both in the model and UI)
data: ['shopping','reading'] // declared in constructor
onPress={() => {this.setState((prevState, props) => {
return {data: [new obj].concat(prevState.data) };
})}}.
this.setState(prevState => ({
Chart: this.state.Chart.length !== 0 ? [...prevState.Chart,data[data.length - 1]] : data
you are breaking React principles, you should clone the old state then merge it with the new data, you shouldn't manipulate your state directly,
your code should go like this
fetch('http://localhost:8080').then(response => response.json()).then(json ={this.setState({mystate[...this.state.mystate, json]}) })
I guess this is a little bit late for an answer but for those new to react
You can use this tiny package called immer
see this example: https://immerjs.github.io/immer/produce
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.