select a.date
from (
select curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a) + (1000 * d.a) ) DAY as date
from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as d
where a.date between '2020-01-20' and '2021-12-24' ORDER BY a.date asc
tips：如果要查询当前日期后面的数据 curdate()改为截止日期就好
2、创建视图可以公共使用
CREATE VIEW v_digits AS
SELECT 0 AS digit UNION ALL
SELECT 1 UNION ALL
SELECT 2 UNION ALL
SELECT 3 UNION ALL
SELECT 4 UNION ALL
SELECT 5 UNION ALL
SELECT 6 UNION ALL
SELECT 7 UNION ALL
SELECT 8 UNION ALL
SELECT 9;
CREATE VIEW v_numbers AS
SELECT
ones.digit + tens.digit * 10 + hundreds.digit * 100 + thousands.digit * 1000 AS number
v_digits as ones,
v_digits as tens,
v_digits as hundreds,
v_digits as thousands;
-- 生成的日期格式为 yyyy-MM-dd
CREATE VIEW v_dates AS
SELECT
SUBDATE(CURRENT_DATE(), number) AS date
v_numbers
UNION ALL
SELECT
ADDDATE(CURRENT_DATE(), number + 1) AS date
v_numbers;
-- 生成的日期格式为 yyyy-MM
CREATE VIEW v_months AS
SELECT
DATE_FORMAT(SUBDATE(CURRENT_DATE(), INTERVAL number MONTH),'%Y-%m') AS date
v_numbers
UNION ALL
SELECT
DATE_FORMAT(ADDDATE(CURRENT_DATE(), INTERVAL number+1 MONTH),"%Y-%m") AS date
v_numbers;
3、创建为视图之后，可以通过视图查询时间区间列表日期
SELECT
v_dates
WHERE
date BETWEEN '2020-01-20' AND '2021-01-24'
ORDER BY
date asc
4、查询时间区间按月
select DATE_FORMAT(str_to_date (a.Date,'%Y-%m-%d'),"%Y-%m") as Date
from (
select '2011-12-24' - INTERVAL (a.a + (10 * b.a) + (100 * c.a) + (1000 * d.a) ) MONTH as Date
from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as d
where a.Date between '2010-01-20' and '2011-12-24' ORDER BY a.Date asc;
附：在对mysql的时间进行区间查询的时候出现的问题
<if test="searchcondition.starttime!=null">
<![CDATA[ and select_data.data_time >= #{searchcondition.starttime,jdbcType=TIMESTAMP} ]]>
<if test="searchcondition.stoptime!=null">
<![CDATA[ and select_data.data_time <= #{searchcondition.stoptime,jdbcType=TIMESTAMP} ]]>
