错误类型JSONArray不能被转换为JSONObject

Question 1

我正在创建一个应用程序，从网络服务器上获取帖子，我得到一个jsonarray到对象的错误，我是安卓开发和教程的新手，我看到JsonArray之前被命名，所以它会是狗的数组，然后里面会有品种和名称等等，地雷没有命名。

我的代码是

public class GetData extends AsyncTask<String, String, String>{
@Override
protected String doInBackground(String... strings) {
    String current = "";
        URL url;
        HttpURLConnection urlConnection = null;
            url = new URL(JSONURL);
            urlConnection = (HttpURLConnection) url.openConnection();
            InputStream in = urlConnection.getInputStream();
            InputStreamReader isr = new InputStreamReader(in);
            int data = isr.read();
            while(data !=-1){
                current += (char) data;
                data = isr.read();
            return current;
        } catch (MalformedURLException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        finally {
            if(urlConnection !=null){
                urlConnection.disconnect();;
    }catch (Exception e){
        e.printStackTrace();
    return current;
@Override
protected void onPostExecute(String s) {
        JSONObject jsonObject = new JSONObject(s);
        JSONArray jsonArray = jsonObject.getJSONArray("");
        for(int i = 0; i<jsonArray.length();i++){
            JSONObject jsonObject1= jsonArray.getJSONObject(i);
            namey = jsonObject1.getString("name");
            post = jsonObject1.getString("post");
            //hashmap
            HashMap<String, String> posts = new HashMap<>();
            posts.put("name", namey);
            posts.put("post", post);
            postList.add(posts);
    } catch (JSONException e) {
        e.printStackTrace();
    //Displaying the results
    ListAdapter adapter = new SimpleAdapter(
            MainActivity.this,
            postList,
            R.layout.item,
            new String[]{"name", "post"},
            new int[]{R.id.textView, R.id.textView2});
    lv.setAdapter(adapter);
我试图解析的json代码是
        "0": "2",
        "id": "2",
        "1": "anon",
        "name": "anon",
        "2": "goodbye people of skivecore",
        "post": "goodbye people of skivecore",
        "3": "38.751053",
        "lat": "38.751053",
        "4": "-90.432915",
        "lng": "-90.432915",
        "5": "",
        "ip": "",
        "6": "6.204982836749738",
        "distance": "6.204982836749738"
        "0": "1",
        "id": "1",
        "1": "anon",
        "name": "anon",
        "2": "hello people of skivecore",
        "post": "hello people of skivecore",
        "3": "38.744453",
        "lat": "38.744453",
        "4": "-90.607986",
        "lng": "-90.607986",
        "5": "",
        "ip": "",
        "6": "9.280600590285143",
        "distance": "9.280600590285143"
和堆栈跟踪信息
2021-04-28 23:45:02.156 20352-20352/com.skivecore.secrets W/System.err: org.json.JSONException: Value [{"0":"2","id":"2","1":"anon","name":"anon","2":"goodbye people of skivecore","post":"goodbye people of skivecore","3":"38.751053","lat":"38.751053","4":"-90.432915","lng":"-90.432915","5":"","ip":"","6":"6.204982836749738","distance":"6.204982836749738"},{"0":"1","id":"1","1":"anon","name":"anon","2":"hello people of skivecore","post":"hello people of skivecore","3":"38.744453","lat":"38.744453","4":"-90.607986","lng":"-90.607986","5":"","ip":"","6":"9.280600590285143","distance":"9.280600590285143"}] of type org.json.JSONArray cannot be converted to JSONObject

Question 2


          
           
            You should use like below
           
           try {
        JSONArray jsonArray = new JSONArray(s);
        for (int i = 0; i < jsonArray.length(); i++) {
            JSONObject jsonObject1 = jsonArray.getJSONObject(i);
            namey = jsonObject1.getString("name");
            post = jsonObject1.getString("post");
            //hashmap
            HashMap<String, String> posts = new HashMap<>();
            posts.put("name", namey);
            posts.put("post", post);
            postList.add(posts);
    } catch (JSONException e) {
        e.printStackTrace();

Question 3


          
           
            
             我认为这里有一个问题
             
              JSONObject jsonObject = new JSONObject(s);
             
             ，因为我可以看到你的响应是一个JSONArray，因为它在开头和结尾都有
             
              [
             
             和
             
              ]
             
             。
            
            
             因此，我认为这将是更合适的。
            
            JSONArray jsonArray = jsonObject.getJSONArray(s);
        for(int i = 0; i<jsonArray.length();i++){
            JSONObject jsonObject1= jsonArray.getJSONObject(i);
            namey = jsonObject1.getString("name");
            post = jsonObject1.getString("post");
            //hashmap
            HashMap<String, String> posts = new HashMap<>();
            posts.put("name", namey);
            posts.put("post", post);
            postList.add(posts);

Question 4


          
           
            
             请使用
             
              gson
             
             库中使用jasonArray和JsonObject Easley
            
            
             1).
             
              
               https://github.com/google/gson
              
             
            
            
             2).libraby导入，然后使用
            
            
             
              
               https://www.jsonschema2pojo.org/
              
             
            
            
             对于你的jsonArray到Model类
            
            
             然后使用jsonArray

Question 5


          
           
            
             用这个代替....
            
            try {
    JSONArray jsonArray = new JSONArray(s);
    for (int i = 0; i < jsonArray.length(); i++) {
        JSONObject jsonObject1 = jsonArray.getJSONObject(i);
        namey = jsonObject1.getString("name");
        post = jsonObject1.getString("post");
        //put to hashmap
        HashMap<String, String> posts = new HashMap<>();
        posts.put("name", namey);
        posts.put("post", post);
        postList.add(posts);