Following is my string

const char* str = "./a.out(__gxx_personality_v0+0x35d) [0x400e5d]";
我只想得到 "0x400e5d "字符串，即括在[和]括号中的子字符串。
I tried following but could not worked:
 char temp[1024];
 sscanf(symbol, "%*[^[]%1023[^]]", temp);
但它给出了"[0x400e5d "的输出。如何避免输出中的"["？
    
c++
regex
linux
scanf
BSalunke
发布于 2014-02-07
1 个回答
Jonathan Leffler
发布于 2014-02-07
已采纳
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