export let i18n: ReturnType<typeof createI18n>; const { t, ...methods } = i18n.global; const tFn: I18nGlobalTranslation = (key: string, ...arg: any[]) => { if (!key) return ''; if (!key.includes('.') && !namespace) return key; return t(getKey(namespace, key), ...(arg as I18nTranslationRestParameters)); }; 报错代码报错his expression is not callable. Each member of the union type 'ComposerTranslation<Record<string, unknown>, unknown, RemoveIndexSignature<{ [x: string]: LocaleMessageValue<VueMessageType>; }>, never, never, never> | VueI18nTranslation<...>' has signatures, but none of those signatures are compatible with each other.

时间: 2024-03-11 20:49:22 浏览: 227

这个错误通常是由于类型不匹配导致的。可能是因为`t`函数的类型定义不正确，或是在调用`t`函数时传递的参数不符合预期。建议检查以下几点： 1. 确保`t`函数的类型定义正确，应该类似于以下代码： ```typescript import { t, Composer } from 'vue-i18n'; type I18nGlobalTranslation = Composer['t']; const tFn: I18nGlobalTranslation = (key: string, ...args: any[]) => { // ... 2. 确保在调用`t`函数时传递的参数类型和数量与`t`函数期望的类型和数量相匹配。在这个错误中，可能是`getKey`函数返回了一个错误的键名，导致`t`函数无法找到对应的翻译内容。你可以在调用`t`函数之前，先打印一下`getKey(namespace, key)`的返回值，检查是否符合预期。如果以上方法都无法解决问题，建议提供更多的代码和错误信息，以便更好地定位问题。

import type { createI18n } from 'vue-i18n'; export let i18n: ReturnType<typeof createI18n>; type I18nGlobalTranslation = { (key: string): string; (key: string, locale: string): string; (key: string, locale: string, list: unknown[]): string; (key: string, locale: string, named: Record<string, unknown>): string; (key: string, list: unknown[]): string; (key: string, named: Record<string, unknown>): string; }; type I18nTranslationRestParameters = [string, any]; function getKey(namespace: string | undefined, key: string) { if (!namespace) { return key; } if (key.startsWith(namespace)) { return key; } return `${namespace}.${key}`; } export function useI18n(namespace?: string): { t: I18nGlobalTranslation; } { const normalFn = { t: (key: string) => { return getKey(namespace, key); }, }; if (!i18n) { return normalFn; } const { t, ...methods } = i18n.global; const tFn: I18nGlobalTranslation = (key: string, ...arg: any[]) => { if (!key) return ''; if (!key.includes('.') && !namespace) return key; return t(getKey(namespace, key), ...(arg as I18nTranslationRestParameters)); }; return { ...methods, t: tFn, }; } // Why write this function？ // Mainly to configure the vscode i18nn ally plugin. This function is only used for routing and menus. Please use useI18n for other places // 为什么要编写此函数？ // 主要用于配合vscode i18nn ally插件。此功能仅用于路由和菜单。请在其他地方使用useI18n export const t = (key: string) => key;这段代码报错，帮忙重写

这段代码报错的原因可能是在使用 useI18n 函数时，参数类型不匹配。可以尝试按照下面的方式重写代码： ```typescript import { createI18n, LocaleMessages } from 'vue-i18n'; const messages: LocaleMessages = { en: { // English translations zh: { // Chinese translations // Add more languages and translations as needed const i18n = createI18n({ locale: 'en', messages, export function useI18n(namespace?: string) { const normalFn = { t: (key: string) => { return namespace ? `${namespace}.${key}` : key; if (!i18n) { return normalFn; const { t, ...methods } = i18n.global; const tFn: I18nGlobalTranslation = ( key: string, ...arg: I18nTranslationRestParameters ) => { if (!key) return ''; if (!key.includes('.') && !namespace) return key; return t(namespace ? `${namespace}.${key}` : key, ...arg); return { ...methods, t: tFn, // This function is only used for routing and menus. Please use useI18n for other places export const t = (key: string) => key; ```