如何在python pandas中对一个列进行base64编码和解码？

我读了这个帖子

对数据框架进行编码

但我不想对数据框架进行加密，只是将其转换为64进制。我将一个以回车为界的单词列表导入到一个数据框架中。

words = pd.read_table("sampleText.txt",names=['word'], header=None)
words.head()
0   difference
1   where
2   mc
3   is
4   the
words['words_encoded'] = map(lambda x: x.encode('base64','strict'), words['word'])
print (words)
                word                   words_encoded
0         difference  <map object at 0x7fad3e89e410>
1              where  <map object at 0x7fad3e89e410>
2                 mc  <map object at 0x7fad3e89e410>
3                 is  <map object at 0x7fad3e89e410>
4                the  <map object at 0x7fad3e89e410>
...              ...                             ...
999995  distribution  <map object at 0x7fad3e89e410>
999996            in  <map object at 0x7fad3e89e410>
999997      scenario  <map object at 0x7fad3e89e410>
999998          less  <map object at 0x7fad3e89e410>
999999          land  <map object at 0x7fad3e89e410>
[1000000 rows x 2 columns]
我不明白为什么我的编码列指的是地图对象而不是实际数据，所以我试了一下。
b64words = words.word.str.encode('base64')
print(b64words)
gives
0        NaN
1        NaN
2        NaN
3        NaN
4        NaN
999995   NaN
999996   NaN
999997   NaN
999998   NaN
999999   NaN
Name: word, Length: 1000000, dtype: float64
Well,
这让我很困惑，所以我阅读了上面的链接答案并尝试了一下
import base64
def encode(text):
    return base64.b64encode(text)
words['Encoded_Column'] = [encode(x) for x in words]
but got
---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-89-8cf5a6f1f3a9> in <module>
      2 def encode(text):
      3     return base64.b64encode(text)
----> 4 words['Encoded_Column'] = [encode(x) for x in words]
<ipython-input-89-8cf5a6f1f3a9> in <listcomp>(.0)
      2 def encode(text):
      3     return base64.b64encode(text)
----> 4 words['Encoded_Column'] = [encode(x) for x in words]
<ipython-input-89-8cf5a6f1f3a9> in encode(text)
      1 import base64
      2 def encode(text):
----> 3     return base64.b64encode(text)
      4 words['Encoded_Column'] = [encode(x) for x in words]
~/miniconda3/envs/p37cu10.2PyTo/lib/python3.7/base64.py in b64encode(s, altchars)
     56     application to e.g. generate url or filesystem safe Base64 strings.
     57     """
---> 58     encoded = binascii.b2a_base64(s, newline=False)
     59     if altchars is not None:
     60         assert len(altchars) == 2, repr(altchars)
TypeError: a bytes-like object is required, not 'str'
所以我试着把它转换为类似字节的对象，就像这样。
import base64
def encode(text):
    btext = text.str.encode('utf-8')
    return base64.b64encode(btext)
words['Encoded_Column'] = [encode(x) for x in words]
but got
---------------------------------------------------------------------------
AttributeError                            Traceback (most recent call last)
<ipython-input-90-46db6d3688ba> in <module>
      3     btext = text.str.encode('utf-8')
      4     return base64.b64encode(btext)
----> 5 words['Encoded_Column'] = [encode(x) for x in words]
<ipython-input-90-46db6d3688ba> in <listcomp>(.0)
      3     btext = text.str.encode('utf-8')
      4     return base64.b64encode(btext)
----> 5 words['Encoded_Column'] = [encode(x) for x in words]
<ipython-input-90-46db6d3688ba> in encode(text)
      1 import base64
      2 def encode(text):
----> 3     btext = text.str.encode('utf-8')
      4     return base64.b64encode(btext)
      5 words['Encoded_Column'] = [encode(x) for x in words]
AttributeError: 'str' object has no attribute 'str'
in this在C语言的例子中，他们也是先转换为字节字符串，然后再转换为base64，但我无法在Python中完成这个简单的任务。我正在掉进这个兔子洞，每次尝试都让我越陷越深。我真的很感谢任何头脑清晰的人能够提供的帮助。