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I am trying to generate the following vector without using c() : a1, b2, b3, c4, c4, c6 . I am having a really hard time with this. I tried to make a simple python function to help visualize it:

listy = []
size = 2
lets = ["a", "b", "c"]
iterator = 1
for i in range(1, 4):
    let = lets[i-1]
    for j in range(3-size):
        listy.append(let + str(iterator))
        iterator += 1
    size -= 1
print(listy)
But I can't get anything similar to work in R. I would greatly appreciate some help.
About the closest I've gotten is this:
paste(rep(1:6), rep(letters[1:3]))
But obviously that's way off. Am I going to have to use for loops to generate this? It seems like there must be a simpler way...
I am new to vector generation and the functions don't seem intuitive at all. If you could just give a poke in the right direction I'm sure I could figure it out. Thanks!
tmp <- rep(vec, seq_along(vec))
paste0(tmp, seq_along(tmp))
#[1] "a1" "b2" "b3" "c4" "c5" "c6"
By hardcoding this is similar to :
paste0(rep(c('a', 'b', 'c'), 1:3), 1:6)
        
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