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I have a method that detects urls in a string and returns me both the urls and the ranges where they can be found. Everything works perfectly until there are emojis on the string. For example:
"I'm gonna do this callenge as soon as I can swing again 😂😂😂\n http://youtu.be/SW_d3fGz1hk"
Because of the emojis, the url extracted from the text is http://youtu.be/SW_d3fGz1 instead of http://youtu.be/SW_d3fGz1hk. I figured that the easiest solution was to just replace the emojis on the string with whitespace characters (cause I need the range to be correct for some text styling stuff). Problem is, this is extremely hard to accomplish with Swift (most likely my abilities with the Swift String API is lacking).
I've been trying to do it like this but it seems that I cannot create a string from an array of unicode points:
var emojilessStringWithSubstitution: String {
let emojiRanges = [0x1F601...0x1F64F, 0x2702...0x27B0]
let emojiSet = Set(emojiRanges.flatten())
let codePoints: [UnicodeScalar] = self.unicodeScalars.map {
if emojiSet.contains(Int($0.value)) {
return UnicodeScalar(32)
return $0
return String(codePoints)
Am I approaching this problem the wrong way? Is replacing emojis the best solution here? If so, how can I do it?
Swift 5
Don't use this hardcoded
way to detect emojis
. In Swift 5
you can do it easily
let inputText = "Some 🖐string 😂😂😂 with 👹👹 👹 emoji 🖐"
let textWithoutEmoij = inputText.unicodeScalars
.filter { !$0.properties.isEmojiPresentation }
.reduce("") { $0 + String($1) }
print(textWithoutEmoij) // Some string with emoji
–
You can use pattern matching (for emoji patterns) to filter out emoji characters from your String
.
extension String {
var emojilessStringWithSubstitution: String {
let emojiPatterns = [UnicodeScalar(0x1F601)...UnicodeScalar(0x1F64F),
UnicodeScalar(0x2702)...UnicodeScalar(0x27B0)]
return self.unicodeScalars
.filter { ucScalar in !(emojiPatterns.contains{ $0 ~= ucScalar }) }
.reduce("") { $0 + String($1) }
/* example usage */
let str = "I'm gonna do this callenge as soon as I can swing again 😂😂😂\n http://youtu.be/SW_d3fGz1hk"
print(str.emojilessStringWithSubstitution)
/* I'm gonna do this callenge as soon as I can swing again
http://youtu.be/SW_d3fGz1hk */
Note that the above only makes use of the emoji intervals as presented in your question, and is in no way representative for all emojis, but the method is general and can swiftly be extended by including additional emoji intervals to the emojiPatterns
array.
I realize reading your question again that you'd prefer substituting emojis with whitespace characters, rather than removing them (which the above filtering solution does). We can achieve this by replacing the .filter
operation above with a conditional return .map
operation instead, much like in your question
extension String {
var emojilessStringWithSubstitution: String {
let emojiPatterns = [UnicodeScalar(0x1F600)...UnicodeScalar(0x1F64F),
UnicodeScalar(0x1F300)...UnicodeScalar(0x1F5FF),
UnicodeScalar(0x1F680)...UnicodeScalar(0x1F6FF),
UnicodeScalar(0x2600)...UnicodeScalar(0x26FF),
UnicodeScalar(0x2700)...UnicodeScalar(0x27BF),
UnicodeScalar(0xFE00)...UnicodeScalar(0xFE0F)]
return self.unicodeScalars
.map { ucScalar in
emojiPatterns.contains{ $0 ~= ucScalar } ? UnicodeScalar(32) : ucScalar }
.reduce("") { $0 + String($1) }
I the above, the existing emoji intervals has been extended, as per your comment to this post (listing these intervals), such that the emoji check is now possibly exhaustive.
–
–
–
–
–
extension String {
func stringByRemovingEmoji() -> String {
return String(self.filter { !$0.isEmoji() })
extension Character {
fileprivate func isEmoji() -> Bool {
return Character(UnicodeScalar(UInt32(0x1d000))!) <= self && self <= Character(UnicodeScalar(UInt32(0x1f77f))!)
|| Character(UnicodeScalar(UInt32(0x2100))!) <= self && self <= Character(UnicodeScalar(UInt32(0x26ff))!)
Emojis are classified as symbols by Unicode. Character sets are typically used in searching operations. So we will use Character sets a property that is symbols.
var emojiString = "Hey there 🖐, welcome"
emojiString = emojiString.components(separatedBy: CharacterSet.symbols).joined()
print(emojiString)
Output is
Hey there , welcome
Now observe the emoji is replaced by a white space so there is two white space and we replace it by the following way
emojiString.replacingOccurrences(of: " ", with: " ")
The above method replace parameter of: "two white space" to with: "single white space"
Getting all emoji is more complicated than you would think. For more info on how to figure out which characters are emoji, check out this stackoverflow post or this article.
Building on that information, I would propose to use the extension on Character to more easily let us understand which characters are emoji. Then add a String extension to easily replace found emoji with another character.
extension Character {
var isSimpleEmoji: Bool {
guard let firstProperties = unicodeScalars.first?.properties else {
return false
return unicodeScalars.count == 1 &&
(firstProperties.isEmojiPresentation ||
firstProperties.generalCategory == .otherSymbol)
var isCombinedIntoEmoji: Bool {
return unicodeScalars.count > 1 &&
unicodeScalars.contains {
$0.properties.isJoinControl ||
$0.properties.isVariationSelector
var isEmoji: Bool {
return isSimpleEmoji || isCombinedIntoEmoji
extension String {
func replaceEmoji(with character: Character) -> String {
return String(map { $0.isEmoji ? character : $0 })
Using it would simply become:
"Some string 😂😂😂 with emoji".replaceEmoji(with: " ")
I found that the solutions given above did not work for certain characters such as 🏋️🏻♂️ and 🧰.
To find the emoji ranges, using regex I converted the full list of emoji characters to a file with just hex values. Then I converted them to decimal format and sorted them. Finally, I wrote a script to find the ranges.
Here is the final Swift extension for isEmoji()
.
extension Character {
func isEmoji() -> Bool {
let emojiRanges = [
(8205, 11093),
(12336, 12953),
(65039, 65039),
(126980, 129685)
let codePoint = self.unicodeScalars[self.unicodeScalars.startIndex].value
for emojiRange in emojiRanges {
if codePoint >= emojiRange.0 && codePoint <= emojiRange.1 {
return true
return false
For reference, here are the python scripts I wrote to parse the hex strings to integers and then find the ranges.
convert-hex-to-decimal.py
decimals = []
with open('hex.txt') as hexfile:
for line in hexfile:
num = int(line, 16)
if num < 256:
continue
decimals.append(num)
decimals = list(set(decimals))
decimals.sort()
with open('decimal.txt', 'w') as decimalfile:
for decimal in decimals:
decimalfile.write(str(decimal) + "\n")
make-ranges.py
first_line = True
range_start = 0
prev = 0
with open('decimal.txt') as hexfile:
for line in hexfile:
if first_line:
prev = int(line)
range_start = prev
first_line = False
continue
curr = int(line)
if prev + 1000 < curr: # 100 is abitrary to reduce number of ranges
print("(" + str(range_start) + ", " + str(prev) + ")")
range_start = curr
prev = curr
Don't hard-code the range of emojis, use this instead.
func 去除表情符号(字符串:String) -> String {
let 转换为Unicode = 字符串.unicodeScalars//https://developer.apple.com/documentation/swift/string
let 去除表情后的结果 = 转换为Unicode.filter { (item) -> Bool in
let 判断是否表情 = item.properties.isEmoji
return !判断是否表情//是表情就不保留
return String(去除表情后的结果)
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