详解Java递归实现树形结构的两种方式

2022-10-24 17:06:04 作者：一宿君
在开发的过程中，很多业务场景需要一个树形结构的结果集进行前端展示，也可以理解为是一个无限父子结构，常见的有报表指标结构、菜单结构等，这篇文章主要介绍了Java递归实现树形结构的两种方式,需要的朋友可以参考下
在开发的过程中，很多业务场景需要一个树形结构的结果集进行前端展示，也可以理解为是一个无限父子结构，常见的有报表指标结构、菜单结构等。Java中递归实现树形结构的两种常见方式如下：
Java7及以下纯Java递归实现
Java8及以上借助lamda表达式实现
1、数据准备

Java实体类NodePO对应数据库表
package com.wbs.pojo;
import lombok.Data;
import lombok.NoArgsConstructor;
import java.util.List;
@Data
@NoArgsConstructor
public class NodePO {
     * 当前节点id
    private String id;
     * 当前节点名称
    private String name;
     * 父级节点id
    private String parentId;
     * 当前节点序号
    private String orderNo;
     * 子集节点
    private List<NodePO> children;
     * 构造函数
     * @param id
     * @param name
     * @param parentId
     * @param orderNo
    public NodePO(String id,String name,String parentId,String orderNo){
        this.id = id;
        this.name = name;
        this.parentId = parentId;
        this.orderNo = orderNo;
 自己造一些数据模拟从数据库中查询出来的数据：
static final List<NodePO> nodePOs = Arrays.asList(
            new NodePO("1","一级节点1",null,"_0001"),
            new NodePO("2","二级节点1.1","1","_0002"),
            new NodePO("3","二级节点1.2","1","_0003"),
            new NodePO("4","一级节点2",null,"_0004"),
            new NodePO("5","二级节点2.1","4","_0005"),
            new NodePO("6","二级节点2.2","4","_0006"),
            new NodePO("7","三级节点2.2.1","6","_0007"),
            new NodePO("8","一级节点3",null,"_0008"),
            new NodePO("9","二级节点3.1","8","_0009"),
            new NodePO("10","三级节点3.1.1","9","_0010"),
            new NodePO("11","四级节点3.1.1.1","10","_0011"),
            new NodePO("12","五级节点3.1.1.1.1","11","_0012")
2、类型转化
从开发的过程中发现直接操作实体类集合，专门指定某一个实体类封装的方法是不具有普适性的，所以将实体类集合统一转化为Map集合，操作方便，具有一定的普适性：
List<Map<String, Object>> mapList = BeanMapUtils.listBeanToListMap(jsonObject);
BeanMapUtils自己简单封装一个工具类（不惧普适性勿喷）：
package com.wbs.util;
import com.alibaba.fastjson.JSON;
import com.alibaba.fastjson.JSONObject;
import com.google.common.collect.Lists;
import com.google.common.collect.Maps;
import lombok.SneakyThrows;
import org.springframework.cglib.beans.BeanMap;
import java.util.*;
import java.util.function.Function;
import java.util.stream.Collectors;
 * @author 一宿君
 * @version Id: BeanMapUtils.java, v 0.1 Administrator Exp $$
 * @date 2022-10-13 14:24:20
 * @desc java实体类和map相互转换工具类
public class BeanMapUtils {
     * 将实体类对象属性转化为map对象
     * @param t
     * @param <T>
     * @return
    public static <T> Map<String, Object> beanToMap(T t) {
        Map<String, Object> map = new HashMap<>();
        if (t != null) {
            if (t instanceof JSONObject){
                return (JSONObject)t;
            BeanMap beanMap = BeanMap.create(t);
            for (Object key : beanMap.keySet()) {
                map.put(key.toString(), beanMap.get(key));
        return map;
     * 将map对象中转化为实体类对象
     * @param map
     * @param clazz
     * @param <T>
     * @return
     * @throws Exception
    public static <T> T mapToBean(Map<String, Object> map,Class<T> clazz) throws Exception {
        T bean = clazz.newInstance();
        if (bean instanceof JSONObject){
            JSONObject jsonObject = (JSONObject)bean;
            Set<Map.Entry<String, Object>> entries = map.entrySet();
            for (Map.Entry<String, Object> entry : entries) {
                jsonObject.put(entry.getKey(),entry.getValue());
            return (T)jsonObject;
        BeanMap beanMap = BeanMap.create(bean);
        beanMap.putAll(map);
        return bean;
     * 通过lambda表达式将List<JavaBean>转化为List<Map<String, Object>>
     * @param objList
     * @param <T>
     * @return
    public static <T> List<Map<String, Object>> listBeanToListMap(List<T> objList) {
        return objList.stream().map(new Function<T, Map<String, Object>>() {
            @Override
            public Map<String, Object> apply(T t) {
                Map<String,Object> map = Maps.newHashMap();
                if (t instanceof JSONObject){
                    return (JSONObject)t;
                BeanMap beanMap = BeanMap.create(t);
                for (Object key : beanMap.keySet()) {
                    map.put(key.toString(), beanMap.get(key));
                return map;
        }).collect(Collectors.toList());
     * 通过lambda表达式将List<Map<String, Object>>转化为List<JavaBean>
     * @param mapList
     * @param <T>
     * @return
    public static <T> List<T> listMapToListBean(List<Map<String,Object>> mapList,Class<T> clazz) {
        return mapList.stream().map(new Function<Map<String, Object>,T>() {
            @SneakyThrows
            @Override
            public T apply(Map<String, Object> map) {
                T t = clazz.newInstance();
                if (t instanceof JSONObject){
                    return (T)map;
                BeanMap beanMap = BeanMap.create(t);
                beanMap.putAll(map);
                return t;
        }).collect(Collectors.toList());
其中org.springframework.cglib.beans.BeanMap;是org.springframework:spring-core依赖下的工具包，spring-core核心依赖只要导入spring-boot-starter依赖即可
<dependency>
    <groupId>org.springframework.boot</groupId>
    <artifactId>spring-boot-starter</artifactId>
    <version>2.2.0.RELEASE</version>
</dependency>
3、递归实现方法
3.1、Java7及以下纯Java递归实现
既然是Java7及以下实现方式，那排序也用最原始的冒泡排序：
     * 冒泡排序,小的在前，大的在后
     * @param list
     * @return
    public static List<Map<String, Object>> sortJava7Map(List<Map<String, Object>> list){
        if(CollectionUtils.isEmpty(list)){
            return Lists.newArrayList();
        boolean flag;
        int size = list.size();
        for (int i = 0; i < size - 1; i++) {
            flag = false;
            for (int j = 1; j < size - i; j++) {
                Map<String, Object> frontMap = list.get(j - 1);
                Map<String, Object> afterMap = list.get(j);
                if (String.valueOf(frontMap.get("orderNo")).compareTo(String.valueOf(afterMap.get("orderNo"))) > 0){
                    list.set(j - 1,afterMap);
                    list.set(j,frontMap);
                    flag = true;
            //如果没有发生位置互换，则退出循环
            if (!flag){
                break;
        return list;
给定一个节点，获取它的所有子节点：
     * Java7及以下版本获取子节点的方式
     * @param parentNode
     * @param allList
     * @return
    public static List<Map<String, Object>> getJava7Children(Map<String,Object> parentNode,List<Map<String, Object>> allList){
        //存放当前节点的直系子节点
        List<Map<String, Object>> curNodeChildrenList = Lists.newArrayList();
        //存放直系子节点以外的节点
        List<Map<String, Object>> otherNodeList = Lists.newArrayList();
        Object pId = parentNode.get("id");
        for (Map<String, Object> map : allList) {
            Object curPId = map.get("parentId");
            if (ObjectUtils.isNotEmpty(curPId) && Objects.equals(pId,curPId)){
                curNodeChildrenList.add(map);
            }else {
                otherNodeList.add(map);
        if (curNodeChildrenList.isEmpty()){
            return curNodeChildrenList;
        //每一层级都进行排序
        curNodeChildrenList = sortJava7Map(curNodeChildrenList);
        //迭代直系子节点再获取子节点
        for (Map<String, Object> map : curNodeChildrenList) {
            map.put("children",getJava7Children(map,otherNodeList));
        return curNodeChildrenList;
给出一个结果集，构建树形结果集：
     * 使用Java7的方式获取树形结构
     * @param allList
     * @return
    public static List<Map<String, Object>> getJava7ResultTree(List<Map<String, Object>> allList){
        //存放所有的一级节点
        List<Map<String, Object>> oneLevelNodeList = Lists.newArrayList();
        for (Map<String, Object> map : allList) {
            if (ObjectUtils.isEmpty(map.get("parentId"))){
                map.put("children",getJava7Children(map,allList));
                oneLevelNodeList.add(map);
        return sortJava8Map(oneLevelNodeList);
获取树形结构：
//转化为Map集合
List<Map<String, Object>> mapList = BeanMapUtils.listBeanToListMap(nodePOs);
//获取树形结构
List<Map<String, Object>> java7ResultTree = getJava7ResultTree(mapList);
//打印输出
System.out.println(JSON.toJSONString(java7ResultTree));
打印结果：
[{"orderNo":"_0001","children":[{"orderNo":"_0002","children":[],"name":"二级节点1.1","id":"2","parentId":"1"},{"orderNo":"_0003","children":[],"name":"二级节点1.2","id":"3","parentId":"1"}],"name":"一级节点1","id":"1"},{"orderNo":"_0004","children":[{"orderNo":"_0005","children":[],"name":"二级节点2.1","id":"5","parentId":"4"},{"orderNo":"_0006","children":[{"orderNo":"_0007","children":[],"name":"三级节点2.2.1","id":"7","parentId":"6"}],"name":"二级节点2.2","id":"6","parentId":"4"}],"name":"一级节点2","id":"4"},{"orderNo":"_0008","children":[{"orderNo":"_0009","children":[{"orderNo":"_0010","children":[{"orderNo":"_0011","children":[{"orderNo":"_0012","children":[],"name":"五级节点3.1.1.1.1","id":"12","parentId":"11"}],"name":"四级节点3.1.1.1","id":"11","parentId":"10"}],"name":"三级节点3.1.1","id":"10","parentId":"9"}],"name":"二级节点3.1","id":"9","parentId":"8"}],"name":"一级节点3","id":"8"}]
树形结构搞定！
3.2、Java8及以上借助lamda表达式实现
Java7的方式虽然实现了树形结构，但是有一定的缺点，比如：代码量比较大，逻辑相对较复杂，那Java8是如何简化，如下所示：
既然Java8有lamda表达式，那代码我们能省就省，先看排序，一行代码搞定：
     * 根据orderNo排序树形结构的每一个层级
     * @param list
     * @return
    public static List<Map<String, Object>> sortJava8Map(List<Map<String, Object>> list){
        if(CollectionUtils.isEmpty(list)){
            return Lists.newArrayList();
        //关键之处，一行代码搞定
        list.sort(Comparator.comparing(m -> String.valueOf(m.get("orderNo"))));
        return list;
给定一个节点，获取它的所有子节点：
释义：
filter： 过滤，相当于for循环，再if条件判断。
peek： 给定一个节点，往它的children塞子节点。
     * 根据父级节点获取所有的子集节点
     * @param parentNode
     * @param allList
     * @return
    public static List<Map<String, Object>> getJava8Children(Map<String,Object> parentNode, List<Map<String, Object>> allList){
        return allList.stream()
                .filter(curNode -> ObjectUtils.isNotEmpty(curNode.get("parentId")) && Objects.equals(curNode.get("parentId"),parentNode.get("id")))
                .peek(m -> m.put("children", getJava8Children(m,allList))).collect(Collectors.toList());
给出一个结果集，构建树形结果集：
     * 获取树形结构
     * @param mapList
     * @return treeList 树形结果集
    public static List<Map<String, Object>> getJava8ResultTree(List<Map<String, Object>> mapList){
        if (CollectionUtils.isEmpty(mapList)){
            return Lists.newArrayList();
        //filter过滤出所有的一级节点
        return mapList.stream().filter(m -> Objects.equals(m.get("parentId"), null) || Objects.equals(m.get("parentId"), ""))
                .peek(m -> m.put("children", sortJava8Map(getJava8Children(m, mapList)))).collect(Collectors.toList());
获取树形结构：
//转化为Map集合
List<Map<String, Object>> mapList = BeanMapUtils.listBeanToListMap(nodePOs);
//获取树形结构
List<Map<String, Object>> java8ResultTree = getJava8ResultTree(mapList);
//打印输出
System.out.println(JSON.toJSONString(java8ResultTree));
打印结果：
[{"orderNo":"_0001","children":[{"orderNo":"_0002","children":[],"name":"二级节点1.1","id":"2","parentId":"1"},{"orderNo":"_0003","children":[],"name":"二级节点1.2","id":"3","parentId":"1"}],"name":"一级节点1","id":"1"},{"orderNo":"_0004","children":[{"orderNo":"_0005","children":[],"name":"二级节点2.1","id":"5","parentId":"4"},{"orderNo":"_0006","children":[{"orderNo":"_0007","children":[],"name":"三级节点2.2.1","id":"7","parentId":"6"}],"name":"二级节点2.2","id":"6","parentId":"4"}],"name":"一级节点2","id":"4"},{"orderNo":"_0008","children":[{"orderNo":"_0009","children":[{"orderNo":"_0010","children":[{"orderNo":"_0011","children":[{"orderNo":"_0012","children":[],"name":"五级节点3.1.1.1.1","id":"12","parentId":"11"}],"name":"四级节点3.1.1.1","id":"11","parentId":"10"}],"name":"三级节点3.1.1","id":"10","parentId":"9"}],"name":"二级节点3.1","id":"9","parentId":"8"}],"name":"一级节点3","id":"8"}]
树形结构搞定！两种实现方式对比一下，你就说Java8的方式哇塞不哇塞！！！
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