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I'm tyring to override the url to call specific methods for different types of urls. Code below

Resources.py

class LCUserResource(ModelResource):
    class Meta:
        queryset = LCUser.objects.all()
        resource_name= 'lcuser'
        authorization = Authorization()
def override_urls(self):
    return [
        url(r'^register/'%
            (self._meta.resource_name, trailing_slash()), self.wrap_view('register_user'), name="api_register_user"),
urls.py
v1_api = Api(api_name='v1')
v1_api.register(LCUserResource())
urlpatterns = [
    url(r'^api/', include(v1_api.urls)),
I'm trying to access the api via  http://localhost:8000/api/v1/lcuser/register/
But i'm getting the error global name urls is not defined.
I tried importing 
from django.conf.urls.defaults import *
Then I get No module named defaults
                Thanks but I'm getting a not all arguments formatted error. I'm using Django 1.8 with tastypie 0.12.2 I'm wondering if my syntax is wrong on my resources.py override url
– Dhanushka Amarakoon
                Jan 15, 2016 at 4:58
The django.conf.urls.default was removed in django 1.6 as stated in the depreciation notes:
  
django.conf.urls.defaults will be removed. The functions include(),
  patterns() and url() plus handler404, handler500, are now available
  through django.conf.urls.
So, it seems like the documentation for tastypie hasn't been updated for django 1.8; you can fix the import error by fixing your import as mentioned in the release note:
from django.conf.urls import url
This will solve one issue - your next problem is here:
r'^register/'% (self._meta.resource_name, trailing_slash())
Not sure you what you are trying to do here as you are parsing a string (with %) but there are no variables to substitute. It is the same problem as this:
>>> a = 'world'
>>> 'hello' % (a,)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: not all arguments converted during string formatting
You probably want the following:
r"^register/(?P<resource_name>%s)%s$" % (self._meta.resource_name, trailing_slash())
                Thanks. I changed the url to ` url(r"^register/", self.wrap_view('register_user'), name="api_register_user"),` and am trying to call it via curl --dump-header - -H "Content-Type: application/json" -X POST --data '{"cellphone": "cell", "password": "pass", "email": "email"}' http://localhost:8000/api/v1/lcuser/register/ But I get the error HTTP/1.0 501 NOT IMPLEMENTED
– Dhanushka Amarakoon
                Jan 18, 2016 at 4:08
                My bad. The url was wrong it should have been url(r"^(?P<resource_name>%s)/register%s$" % (self._meta.resource_name, trailing_slash()), self.wrap_view('register_user'), name="api_register_user"),
– Dhanushka Amarakoon
                Jan 18, 2016 at 5:04
                This is  getting out of topic but how do I access request Data? request.data['email'] returns an error
– Dhanushka Amarakoon
                Jan 18, 2016 at 5:20
        
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