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I have searched around
Func<>
and
Action<>
but I have no idea.
The original Java code of
Consumer.accept()
interface is pretty simple. But not for me:
void accept(T t);
* Returns a composed {@code Consumer} that performs, in sequence, this
* operation followed by the {@code after} operation. If performing either
* operation throws an exception, it is relayed to the caller of the
* composed operation. If performing this operation throws an exception,
* the {@code after} operation will not be performed.
* @param after the operation to perform after this operation
* @return a composed {@code Consumer} that performs in sequence this
* operation followed by the {@code after} operation
* @throws NullPointerException if {@code after} is null
default Consumer<T> andThen(Consumer<? super T> after) {
Objects.requireNonNull(after);
return (T t) -> { accept(t); after.accept(t); };
–
–
–
–
"Consumer interface represents an operation that accepts a single
input argument and returns no result"
Well, provided that the quote above taken from here is accurate it’s roughly an equivalent of Action<T>
delegate in C#;
For example this java code:
import java.util.function.Consumer;
public class Main {
public static void main(String[] args) {
Consumer<String> c = (x) -> System.out.println(x.toLowerCase());
c.accept("Java2s.com");
Converted to C# would be:
using System;
public class Main
static void Main(string[] args)
Action<string> c = (x) => Console.WriteLine(x.ToLower());
c.Invoke("Java2s.com"); // or simply c("Java2s.com");
Consumer<T>
corresponds to Action<T>
and the andThen
method is a sequencing operator. You can define andThen
as an extension method e.g.
public static Action<T> AndThen<T>(this Action<T> first, Action<T> next)
return e => { first(e); next(e); };
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