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I want to plot some points with the rbf function like here to get the density distribution of the points:
if i run the following code, it works fine:
from scipy.interpolate.rbf import Rbf # radial basis functions
import cv2
import matplotlib.pyplot as plt
import numpy as np
# import data
x = [1, 1, 2 ,3, 2, 7, 8, 6, 6, 7, 6.5, 7.5, 9, 8, 9, 8.5]
y = [0, 2, 5, 6, 1, 2, 9, 2, 3, 3, 2.5, 2, 8, 8, 9, 8.5]
d = np.ones(len(x))
print(d)
ti = np.linspace(-1,10)
xx, yy = np.meshgrid(ti, ti)
rbf = Rbf(x, y, d, function='gaussian')
jet = cm = plt.get_cmap('jet')
zz = rbf(xx, yy)
plt.pcolor(xx, yy, zz, cmap=jet)
plt.colorbar()
# Plotting the original points.
plot3 = plt.plot(x, y, 'ko', markersize=5) # the original points.
plt.show()
Now I want to change my input data:
# import data
input = "testProbe.jpg"
image = cv2.imread(input) # load the image
gray = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY) # convert it to grayscale
# threshold the image to reveal light regions in the gray image
thresh = cv2.threshold(gray, 145, 200, cv2.THRESH_BINARY)[1]
x, y = np.where(thresh > 0)
d = np.ones(len(x))
And I get the following error message:
Traceback (most recent call last):
File "C:/Users/.../Python/pythonprojects/03a_test_rbfWithScipy.py", line 32, in <module>
rbf = Rbf(x, y, z, function='gaussian')
File "C:\Users\...\Python\Anaconda2\lib\site-packages\scipy\interpolate\rbf.py", line 220, in __init__
self.nodes = linalg.solve(self.A, self.di)
File "C:\Users\...\Python\Anaconda2\lib\site-packages\scipy\interpolate\rbf.py", line 226, in A
r = self._call_norm(self.xi, self.xi)
File "C:\Users\...\Python\Anaconda2\lib\site-packages\scipy\interpolate\rbf.py", line 236, in _call_norm
return self.norm(x1, x2)
File "C:\Users\...\Python\Anaconda2\lib\site-packages\scipy\interpolate\rbf.py", line 118, in _euclidean_norm
return np.sqrt(((x1 - x2)**2).sum(axis=0))
MemoryError
The error message appears really fast and when I look at the task manager, the PC is not running at full capacity. He issues this message immediately. Something can't be right then, can't it?
I tried it with other threshold values thresh = cv2.threshold(gray, 250, 255, cv2.THRESH_BINARY)[1] to get less values and it works although I get the following error message:
C:\Users\...\Python\Anaconda2\lib\site-packages\scipy\interpolate\rbf.py:220: LinAlgWarning:
scipy.linalg.solve Ill-conditioned matrix detected. Result is not guaranteed to be accurate.
Reciprocal condition number2.246772e-22 self.nodes = linalg.solve(self.A, self.di)
Any ideas?
If I only cut out a small part of the picture, then it works too. Maybe it makes some preliminary calculation for the memory and gives me the memory error
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It appears to me Rbf interpolation is quite computationally intensive and leads to O(N^2) operations (correct me if I am wrong). So in order to avoid memory error you can do one of the following, instead of
zz = rbf(xx, yy)
1. Iterate with nditer
Slow, but works for small arrays:
for iz, ix, iy in np.nditer(
[zz, xx, yy],
flags=['external_loop', 'buffered'],
op_flags=['readwrite']
iz[...] = rbf(ix, iy)
2. Use dask.array
Faster option and uses threads
import dask.array as da
n1 = xx.shape[1]
ix = da.from_array(xx, chunks=(1, n1))
iy = da.from_array(yy, chunks=(1, n1))
iz = da.map_blocks(rbf, ix, iy)
zz = iz.compute()
Hope this works for you.
P.S: As suggested on another question and scipy docs on Rbf, Rbf also allows you to replace the norm calculation function with a callable (see LowLevelCallable and the Pythran blog). It is a bit involved, but it might also solve your problem, while increasing the performance as well.
P.P.S: I managed to speedup by a factor of 50 by making this modification:
import numpy as np
def euclidean_norm_numpy(x1, x2):
return np.linalg.norm(x1 - x2, axis=0)
rbf = Rbf(x, y, d, function='gaussian', norm=euclidean_norm_numpy)
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